Answer:
KMnO4,H3O^+,75°C
Explanation:
The conversion of cyclohexene to trans-1,2-cylohexanediol is an oxidation reaction. Alkenes are oxidized in the presence of potassium permanganate and acids to yield the corresponding diols.
These diols may also be called glycols. They are molecules that contain two -OH(hydroxyl) groups per molecule. The reaction closely resembles the addition of the two -OH groups of hydrogen peroxide to an alkene.
The bright color of potassium permanganate disappears in this reaction so it can be used as a test for alkenes.
Answer:
C. An 1s orbital
Explanation:
At the first energy level, the only orbital available to electrons is the 1s orbital, but at the second level, as well as a 2s orbital, there are also orbitals called 2p orbitals.
Answer:
Ksp = 7.4x10⁻⁷
Explanation:
Molar solubility of a substance is defined as the amount of moles of that can be dissolved per liter of solution.
Ksp of Zn(OH)₂ is:
Zn(OH)₂(s) ⇄ Zn²⁺ + 2OH⁻
Ksp = [Zn²⁺] [OH⁻]²
And the molar solubility, X, is:
Zn(OH)₂(s) ⇄ Zn²⁺ + 2OH⁻
⇄ X + 2X
<em>Because X are moles of substance dissolved.</em>
<em>Ksp = </em>[X] [2X]²
Ksp = 4X³
As molar solubility, X, is 5.7x10⁻³mol/L:
Ksp = 4X³
Ksp = 4 (5.7x10⁻³mol/L)³
<h3>Ksp = 7.4x10⁻⁷</h3>
The answer is yes they do form ions upon gaining electrons and becomes negatively charged
If we use the next formula to determine this:<span>ΔQ=mcΔT
Then we can get to the result. Be</span>cause of the conservation of energy, the quantity of heat remains the same.
So what we do is:<span><span>c1</span>∗<span>m1</span>∗(<span>T1</span>−<span>T∗</span>)=<span>c2</span>∗<span>m2</span>∗(<span>T∗</span>−<span>T2</span>)</span><span>
when plugging in 0.39 for copper and 4.19 we get 29°C for the resulting temperature. I hope this can help you</span>
