Answer:
Okay ask away. . . You haven't asked anything that we would be able to answer
when Kc = [the concentration of products]^(no.of its mol in the balanced equation) / [the concentration of the reactants]^(no.of mol in the balanced equation)
∴ The equilibrium constant expression for this reaction is:
Kc= [H+]^2 * [So4-2] / [H2SO4]
Answer:
1. A. Thyroid Gland Function
B. detecting Blood Clots
C. Treating Cancer
2. An example would be how many are used as tracers for diagnostic purposes
3. Beneficial because it gives us ways to eleminate pests, by the sterile insect technique
Number three is kinda iffy a bit difficult to explain it may be explained better in your book.
Answer:
the "d" option
Explanation:
Cómo se pronuncia
To calculate the flow I need the volume and time to comply with the formula:
S = V / t
V = volume
t = time
In this problem I have volume and density as data.
There is no way to calculate the time so the correct answer is the "d" option
Answer: Option (d) is the correct answer.
Explanation:
A reaction in which there occurs change in oxidation state of reacting species is known as an oxidation-reduction reaction.
(a)
Will be written as:

In this reaction, there occurs no change in oxidation state of reacting species. Hence, it is not an oxidation-reduction reaction.
(b) 
Will be written as:

Similarly here, there occurs no change in oxidation state of reacting species. Hence, it is not an oxidation-reduction reaction.
(c) 
Will be written as:

Here, also there occurs no change in oxidation state of reacting species. Hence, it is not an oxidation-reduction reaction.
(d) 
So, here there occurs change in oxidation state of Mg from 0 to +2 and oxidation state of H changes from +1 to 0. Hence, it is an oxidation-reduction reaction.
Thus, we can conclude that
is an oxidation-reduction reaction.