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horsena [70]
3 years ago
5

In ΔVWX, m ∠ V = ( 5 x + 7 ) ∘ m∠V=(5x+7) ∘ , m ∠ W = ( 4 x + 16 ) ∘ m∠W=(4x+16) ∘ , and m ∠ X = ( 5 x + 17 ) ∘ m∠X=(5x+17) ∘ .

What is the value of x ? x?
Mathematics
1 answer:
Otrada [13]3 years ago
6 0

Answer:

idkyuhhggrtwuoiwe

Step-by-step explanation:

IFNDKS

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A field is to be fertilized at a cost of $0.08 per square yard. The rectangular part of the field is 95 yards long and the diame
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this gives
total area of the field = 4655 sqyrd + 1884.79 sqyrd = 6539.79 sqyrd
 cost of fertilising 1 sqyrd = $ 0.08
 so cost of fertilising 6539.79 sqyrd = 6539.79 * $ 0.08 = $ 523.18

6 0
3 years ago
3. The Luxor hotel, in Las Vegas, is a square pyramid with lateral faces consisting of black, glassed mirrored panes. The buildi
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Given: 
Square pyramid with lateral faces.
646 ft wide at the base.
350 ft high.

Because of the term lateral faces, we need to get the lateral area of the square pyramid.

Lateral Area = a √a² + 4 h² ; a = 646 ft ; h = 350 ft

L.A. = 646 ft √(646ft)² + 4 (350ft)²
L.A. = 646 ft √417,316 ft² + 4 (122,500 ft²)
L.A. = 646 ft √417,316 ft² + 490,000 ft²
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3 0
3 years ago
An independent-measures research study compares three treatment conditions using a sample of n = 5 in each treatment. For this s
slavikrds [6]

Answer: c. ​10

Step-by-step explanation:

Given : An independent-measures research study compares three treatment conditions using a sample of n = 5 in each treatment.

For this study, the three sample means are, M1 = 1, M2 = 2, and M3 = 3.

Grand mean = \overline{X}=\dfrac{M1+M2+M3}{3} [All sample have equal elements]

=\dfrac{1+2+3}{3}=2

For ANOVA,

SS_{between}=n\sum(M_i-\overline{X})^2 , where i= 1, 2 , 3

SS_{between}=5((1-2)^2+(2-2)^2+((3-2)^2)

SS_{between}=5((-1)^2+(0)^2+((1)^2)= 5(1+1)=10

Hence,the value would be obtained for SS_{between}=10 .

hence, the correct answer = c. ​10

8 0
3 years ago
Please help will give brainliest if you answer correct
adell [148]
You’re answer is y=-1/1.5x+2.5
Explanation
2.5 is you’re y intersect and you go over one < and up 1.5
7 0
2 years ago
a study was to be undertaken to determine if a particular training program would improve physical fitness. an srs of 31 universi
Nataliya [291]

Step-by-step explanation:

A study was to be undertaken to determine if a particular training program would improve physical fitness. A sample of 31 university students was selected to be enrolled in the fitness program. The researchers wished to determine if there was evidence that their sample of students differed from the general population of untrained subjects. The sample mean is 47.4 and a standard deviation of 5.3. The 98% confidence interval is determined and is given as, (45.2, 49.6) .

If the level of confidence is changed to 95%, then the confidence interval will become shorter but the p-value will not change because it is calculated using the test statistic. So the correct answer is (a).

3 0
1 year ago
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