Answer:
Oxidized : CO
Reduced: Fe
Oxidizing agent: Fe2O3
Reducing agent: CO
Explanation:
Loss of electrons is oxidation while gaining of electrons is reduction.
CO is a reducing agent, Fe2O3 is an oxidizing agent.
Each carbon atom is oxidized in CO. CO is the reducing agent
Each Fe atom in FeO3 is reduced. FeO3 is the oxidizing agent
2Ca + O2 = 2CaO
First, determine which is the excess reactant
72.5 g Ca (1 mol) =1.8089725036
(40.078 g)
65 g O2 (1 mol) =2.0313769611
(15.999g × 2)
Since the ratio of to O2 is 2:1 in the balanced reaction, divide Ca's molar mass by 2 to get 0.9044862518. this isn't necessary because Ca is already obviously the limiting reactant. therefore, O2 is the excess reactant.
Now do the stoichiometry
72.5 g Ca (1 mol Ca) (1 mol O2)
(40.078 g Ca)(2 mol Ca)(31.998g O2)
=0.0282669621 g of O2 left over
Answer:
16:1
Explanation:
Atoms of element X weigh 32 times more than atoms of element Y. We can write this in a symbolic way.
mX = 32 mY [1]
where,
- mX and mY are the masses of X and Y, respectively
A compound has the formula: XY₂, that is, in 1 molecule of XY₂ there is 1 atom of X and 2 atoms of Y. The ratio of the mass of X to the mass of Y in this compound equals:
mX/2 mY [2]
If we substitute [1] in [2], we get:
mX/2 mY = 32 mY/2 mY = 16 = 16:1
Answer: A volume of .5650 what? And what unit will be considered?
Explanation:
Molar mass of O2: 32g/mol
Moles of O2 = 19.5 / 32 = 0.609mol
