Answer:
V = 0.24 L.
Explanation:
Hello there!
In this case, it is possible to approach this problem by using the ideal gas equation defined by:
![PV=nRT](https://tex.z-dn.net/?f=PV%3DnRT)
Whereas our unknown is V, volume, and we solve for it as follows:
![V=\frac{nRT}{P}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7BnRT%7D%7BP%7D)
Then since the STP conditions are ate 273.15 K and 1 atm, the volume of 0.011 moles of CO2 gas turns out to be:
![V=\frac{0.011mol*0.08206\frac{atm*L}{mol*K}*273.15K}{1atm}\\\\V=0.24L](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B0.011mol%2A0.08206%5Cfrac%7Batm%2AL%7D%7Bmol%2AK%7D%2A273.15K%7D%7B1atm%7D%5C%5C%5C%5CV%3D0.24L)
Regards!
The answer is B. physical deposition because freezing and thawing are physical factors that affect weathering.
The answer is C. The others are either a compound or an element