Answer:
The answer is "26179.4".
Step-by-step explanation:
Assume year 2000 as t, that is t =0.
Formula:
![A= A_0e^{rt}](https://tex.z-dn.net/?f=A%3D%20A_0e%5E%7Brt%7D)
Where,
![A_0 = \ initial \ pop \\\\r= \ rate \ in \ decimal \\\\t= \ time \ in \ year](https://tex.z-dn.net/?f=A_0%20%3D%20%5C%20initial%20%5C%20pop%20%5C%5C%5C%5Cr%3D%20%5C%20rate%20%5C%20in%20%5C%20decimal%20%5C%5C%5C%5Ct%3D%20%5C%20time%20%5C%20in%20%5C%20year)
for doubling time,
![r = \frac{log (2)}{t} \\](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7Blog%20%282%29%7D%7Bt%7D%20%5C%5C)
![r = \frac{\log (2)}{ 40} \\\\r= \frac{0.301}{40}\\\\r= 0.007](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7B%5Clog%20%282%29%7D%7B%2040%7D%20%5C%5C%5C%5Cr%3D%20%5Cfrac%7B0.301%7D%7B40%7D%5C%5C%5C%5Cr%3D%200.007)
Given value:
![A = A_0e^{rt} \\\\](https://tex.z-dn.net/?f=A%20%3D%20A_0e%5E%7Brt%7D%20%5C%5C%5C%5C)
![A_0 = 13000](https://tex.z-dn.net/?f=A_0%20%3D%2013000)
![t= 40 \ years](https://tex.z-dn.net/?f=t%3D%2040%20%5C%20years)
when year is 2000, t=0 so, year is 2100 year as t = 100.
![A = 13000 \times e^{et}\\\\A = 13000 \times e^{e \times t}\\\\A = 13000 \times e^{0.007 \times 100}\\\\A = 13000 \times e^{0.7}\\\\A= 13000\times 2.0138\\\\A = 26179.4](https://tex.z-dn.net/?f=A%20%3D%2013000%20%5Ctimes%20e%5E%7Bet%7D%5C%5C%5C%5CA%20%3D%2013000%20%5Ctimes%20e%5E%7Be%20%5Ctimes%20t%7D%5C%5C%5C%5CA%20%3D%2013000%20%5Ctimes%20e%5E%7B0.007%20%5Ctimes%20100%7D%5C%5C%5C%5CA%20%3D%2013000%20%5Ctimes%20e%5E%7B0.7%7D%5C%5C%5C%5CA%3D%2013000%5Ctimes%202.0138%5C%5C%5C%5CA%20%3D%2026179.4)
10.99 +11.67+ 3.64 + 2.83 = 29.13 SO THE TAX EQUALS 87 CENTS
Answer:
Move the decimal two times to the left and you get 1.5638
Answer: |p-72% |≤ 4%
Step-by-step explanation:
Let p be the population proportion.
The absolute inequality about p using an absolute value inequality.:
, where E = margin of error,
= sample proportion
Given: A poll result of 72% with a margin of error of 4% indicates that p is most likely to be between 68% and 76% .
|p-72% |≤ 4%
⇒ 72% - 4% ≤ p ≤ 72% +4%
⇒ 68% ≤ p ≤ 76%.
i.e. p is most likely to be between 68% and 76% (.