Answer:
a) The value of A = 2
b) The value of 
Step-by-step explanation:
a)
Given that:
X should be the random variable that assumes only positive integer values.
The probability function;
for some constant A and n ≥ 1.
Then, let ![\sum \limits ^{\infty}_{n =1} P[X =n] = 1](https://tex.z-dn.net/?f=%5Csum%20%5Climits%20%5E%7B%5Cinfty%7D_%7Bn%20%3D1%7D%20P%5BX%20%3Dn%5D%20%3D%201)
This implies that:




A = 2
Thus, the value of A = 2
b)
Suppose X represents a e constant A (n> 1). Find A.
b) Let X be a continuous random variable that can assume values between 0 and 3
Then, the density function of x is:

where; B is constant.
Then, using the property of the probability density function:

Taking the integral, we have:
![B \Big [\dfrac{x^3}{3} +x \Big ]^3_0 = 1](https://tex.z-dn.net/?f=B%20%5CBig%20%5B%5Cdfrac%7Bx%5E3%7D%7B3%7D%20%2Bx%20%5CBig%20%5D%5E3_0%20%3D%201)
![B \Big [\dfrac{3^3}{3} +3 \Big ]= 1](https://tex.z-dn.net/?f=B%20%5CBig%20%5B%5Cdfrac%7B3%5E3%7D%7B3%7D%20%2B3%20%5CBig%20%5D%3D%201)
![B \Big [\dfrac{27}{3} +3 \Big ] = 1](https://tex.z-dn.net/?f=B%20%5CBig%20%5B%5Cdfrac%7B27%7D%7B3%7D%20%2B3%20%5CBig%20%5D%20%3D%201)
B [ 9 +3 ] = 1
B [ 12 ] = 1
Divide both sides by 12

Answer:
Multiply the term outside of the parentheses by each term in the parentheses. To do this, you are essentially distributing the outer term into the inner terms. Multiply the term outside the parentheses by the first term in the parentheses. Then multiply it by the second term. If there are more than two terms, keep distributing the term until there are no terms left. Keep whatever operation (plus or minus) is in the parentheses
Step-by-step explanation:
Answer:
11-19 pounds
Step-by-step explanation:
In standard/numbers form:
1,229,000,003