<h3>Jason bought 20 stamps of $0.41 each and 8 postcards of $0.26 each.</h3>
<em><u>Solution:</u></em>
Let stamps be s and postcards be p
Given that,
The number of stamps was 4 more than twice the number of postcards
s = 4 + 2p -------- eqn 1
Jason bought both 41-cent stamps and 26-cent postcards and spent $10.28
41 cent = $ 0.41
26 cent = $ 0.26
Therefore,

0.41s + 0.26p = 10.28 --------- eqn 2
Substitute eqn 1 in eqn 2
0.41(4 + 2p) + 0.26p = 10.28
1.64 + 0.82p + 0.26p = 10.28
1.08p = 10.28 - 1.64
1.08p = 8.64
Divide both sides by 1.08
p = 8
Substitute p = 8 in eqn 1
s = 4 + 2(8)
s = 4 + 16
s = 20
Thus Jason bought 20 stamps and 8 post cards
x = -21
explanation: a trick i used was just do -3 times 7 and get my answer -21. if you are unsure if the answer is right just check your work with a calculator. -21 divided by 7 is -3 so -21 is the value of x. please mark brainliest !!
Answer:
x = 11.25
Step-by-step explanation:
-6 = 0.8x - 15
Add 15 to both sides;
-6 + 15 = 0.8x - 15 + 15
9 = 0.8x
Divide both sides by 0.8;
x = 11.25
The answer is –x + 5 = 6x - 2. This is because of the Transitive Property.
You most likely remember the transitive property as "if a = b and b = c, then a = c." In this case, if y = -x + 5 and y = 6x - 2, then -x + 5 = 6x - 2.