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Andre45 [30]
3 years ago
9

[25 points] Help with proportions, I don't understand! 134 out of 205 families in "Chimgan" village keep cows, 142 keep sheep an

d 76 keep goats. 67 families have cows and sheep, 10 have cows and goats, 15 have sheep and goats. There are 34 families who keep all three kinds of pets. a) How many families keep only one kind of pet?
b) How many have no pets at all? Hint: Use the following diagram.​

Mathematics
1 answer:
Shalnov [3]3 years ago
5 0

Answer:

only keeps-

cows=134-67-34-10=23

sheep=142-67-34-15=26

goats=76-10-34-15=17

no pets=205-23-17-26-67-10-16-34

Step-by-step explanation:

some have one pets some have two or three

total no. of family have cows is 134 then 134 minus by those with more will be no. of family only with cows

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Ymorist [56]

Answer:

You can follow the following method, there are other ways to do this too.

Step-by-step explanation:

Taking RHS,

(cosx-sinx+cosx+sinx)/(cos^2x-sin^2) [Taking LCM of den.]

2cosx/cos2x

Taking LHS,

sin2x/cos2x*1/sinx

2sinxcosx/cos2x*1/sinx

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3 years ago
A certain bacteria colony doubles in size every day for 20 days, at which point it reaches the limit of its habitat and can no l
erma4kov [3.2K]

Answer:

(E). 19

Step-by-step explanation:

Let original population of each colony be P.

We have been given that a certain bacteria colony doubles in size every day, so bacteria colony is growing exponentially. After x days, the population of bacteria would be:

P(2)^x

The population after 19 days will be P(2)^{19} for each colony.

The total population of both the colonies at that point will be P(2)^{19}+P(2)^{19}=2P(2)^{19}=P(2)^{20} which is what the habitat's limit is.

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4 years ago
ΔACB • ΔEFD
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Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

PO = 36

Step-by-step explanation:

Since both the chords are equal in length so they must be equidistant from the centre.

And

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x = -8

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