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aleksklad [387]

2 years ago

11

How many one-half cubes with dimensions of One-half times 1 times 1 fit in a unit cube?

2 answers:

jek_recluse [69]2 years ago

7 0

Answer:

4 i think

Step-by-step explanation:

iragen [17]2 years ago

5 0

i think 2 but i dont know for sure ahahahaha

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Identify an equation in point-slope for the parallel to y=3/4x-4 that passes through (-1,7)

Nikitich [7]

The answer is B! Ive past my test for this task.

4 0

3 years ago

1. an alloy contains zinc and copper in the ratio of 7:9 find weight of copper of it had 31.5 kgs of zinc.

m_a_m_a [10]

Answer:

Step-by-step explanation:

Question (1). An alloy contains zinc and copper in the ratio of 7 : 9.

If the weight of an alloy = x kgs

Then weight of copper = $\frac{9}{7+9}\times (x)$

= $\frac{9}{16}\times (x)$

And the weight of zinc = $\frac{7}{7+9}\times (x)$

= $\frac{7}{16}\times (x)$

If the weight of zinc = 31.5 kg

31.5 = $\frac{7}{16}\times (x)$

x = $\frac{16\times 31.5}{7}$

x = 72 kgs

Therefore, weight of copper = $\frac{9}{16}\times (72)$

= 40.5 kgs

2). i). 2 : 3 = $\frac{2}{3}$

4 : 5 = $\frac{4}{5}$

Now we will equalize the denominators of each fraction to compare the ratios.

$\frac{2}{3}\times \frac{5}{5}$ = $\frac{10}{15}$

$\frac{4}{5}\times \frac{3}{3}=\frac{12}{15}$

Since, $\frac{12}{15}>\frac{10}{15}$

Therefore, 4 : 5 > 2 : 3

ii). 11 : 19 = $\frac{11}{19}$

19 : 21 = $\frac{19}{21}$

By equalizing denominators of the given fractions,

$\frac{11}{19}\times \frac{21}{21}=\frac{231}{399}$

And $\frac{19}{21}\times \frac{19}{19}=\frac{361}{399}$

Since, $\frac{361}{399}>\frac{231}{399}$

Therefore, 19 : 21 > 11 : 19

iii). $\frac{1}{2}:\frac{1}{3}=\frac{1}{2}\times \frac{3}{1}$

$=\frac{3}{2}$

$\frac{1}{3}:\frac{1}{4}=\frac{1}{3}\times \frac{4}{1}$

= $\frac{4}{3}$

Now we equalize the denominators of the fractions,

$\frac{3}{2}\times \frac{3}{3}=\frac{9}{6}$

And $\frac{4}{3}\times \frac{2}{2}=\frac{8}{6}$

Since $\frac{9}{6}>\frac{8}{6}$

Therefore, $\frac{1}{2}:\frac{1}{3}>\frac{1}{3}:\frac{1}{4}$ will be the answer.

IV). $1\frac{1}{5}:1\frac{1}{3}=\frac{6}{5}:\frac{4}{3}$

$=\frac{6}{5}\times \frac{3}{4}$

$=\frac{18}{20}$

$=\frac{9}{10}$

Similarly, $\frac{2}{5}:\frac{3}{2}=\frac{2}{5}\times \frac{2}{3}$

$=\frac{4}{15}$

By equalizing the denominators,

$\frac{9}{10}\times \frac{30}{30}=\frac{270}{300}$

Similarly, $\frac{4}{15}\times \frac{20}{20}=\frac{80}{300}$

Since $\frac{270}{300}>\frac{80}{300}$

Therefore, $1\frac{1}{5}:1\frac{1}{3}>\frac{2}{5}:\frac{3}{2}$

V). If a : b = 6 : 5

$\frac{a}{b}=\frac{6}{5}$

$=\frac{6}{5}\times \frac{2}{2}$

$=\frac{12}{10}$

And b : c = 10 : 9

$\frac{b}{c}=\frac{10}{9}$

Since a : b = 12 : 10

And b : c = 10 : 9

Since b = 10 is common in both the ratios,

Therefore, combined form of the ratios will be,

a : b : c = 12 : 10 : 9

7 0

3 years ago

Can anyone tell me if this is right

Rashid [163]

Answer:

yes it is correct

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

The weight of an object is equal to 3\4 of its own weight plus 3\4of a pound. What is the weight?

Phoenix [80]

Answer:

The weight of the object is 3 kg.

Step-by-step explanation:

<u>Step 1: </u>

Let object weight be x kg.

Now, as per the available data,

3/4 kg + 3/4 (x kg) = x kg

<u>Step 2: </u>

3/4 (1 + x) = x

1 + x = 4x/3

1 = x (4/3 - 1)

x = 1 / (1/3)

x = 3

Weight of Object is 3 kg.

<u>Step 3: </u>

Let's check if this value satisfies the first equation.

3/4 + 3/4 x 3 = 3/4 + 9/4 = 12/4 = 3

Hence proved.

8 0

3 years ago

Need help asap The answer is 100 or 126

Serga [27]

Answer:

The surface area of the cone is 126π cm².

Step-by-step explanation:

The surface area of a cone can be found using this formula:

$\text{SA} = \pi r ^2+\pi r l$
where r = radius and l = slant height

In this problem, we are told that the cone has a radius of 9 cm and a slant height of 5 cm.

Substitute these values into the formula for the surface area of a cone.

$\text{SA}= \pi (9)^2+ \pi(9)(5)\\$
$\text{SA}= \pi (81)+ \pi(45)$
$\text{SA}= 126 \pi$

The surface area of the right cone is 126 π cm².

6 0

2 years ago