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nordsb [41]
3 years ago
11

Find KL. URGENT!!!!!!

Mathematics
1 answer:
natali 33 [55]3 years ago
3 0
<h2>KL = 27</h2><h2>------------------------------</h2>

<u>Step-by-step explanation:</u>

JM = 27 ---- ( given )

JM = KL

so, KL = 27

<h2>------------------------------</h2><h2>FOLLOW ME</h2>
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Solve this equation for x: 2x^2 + 12x - 7 = 0
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Answer:

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First step is to: Isolate the constant term by adding 7 to both sides

Step-by-step explanation:

We want to solve this equation: 2x^2 + 12x - 7 = 0

On observation, the trinomial is not factorizable so we use the Completing the square method.

Step 1: Isolate the constant term by adding 7 to both sides

2x^2 + 12x - 7+7 = 0+7\\2x^2 + 12x=7

Step 2: Divide the equation all through by the coefficient of x^2 which is 2.

x^2 + 6x=\frac{7}{2}

Step 3: Divide the coefficient of x by 2, square it and add it to both sides.

Coefficient of x=6

Divided by 2=3

Square of 3=3^2

Therefore, we have:

x^2 + 6x+3^2=\frac{7}{2}+3^2

Step 4: Write the Left Hand side in the form (x+k)^2

(x+3)^2=\frac{7}{2}+3^2\\(x+3)^2=12.5\\

Step 5: Take the square root of both sides and solve for x

x+3=\pm\sqrt{12.5}\\x=-3\pm \sqrt{12.5}\\x=-3+ \sqrt{12.5}, $ or $x= -3- \sqrt{12.5}\\$x=0.5355 or x=-6.5355

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