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kherson [118]
3 years ago
5

The mean of a set of normally distributed data is 600 with a standard devastation of 20. What percent of data is between 580 and

620
Mathematics
1 answer:
yuradex [85]3 years ago
3 0

Answer: 68%

Step-by-step explanation:

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The center on a target has a diameter of 5 inches. The whole target has a diameter of 25 inches. Complete the explanation for wh
kicyunya [14]

Answer:

The center is \frac{1}{25} of the whole target.

Step-by-step explanation:

Given:

Diameter of the center = 5 inches

Diameter of the whole target = 25 inches

We need to find the part of the center to the whole target.

Solution,

Firstly we will find out the areas of center and whole target.

For center;

Diameter = 5 in

Radius of circle is equal to half of the diameter.

radius = \frac{diameter}{2}=\frac{5}{2}=2.5\ in

Now we know that the area of circle is equal to π times square of the radius.

framing in equation form, we get;

Area = \pi \times{2.5}^2

For whole target;

Diameter = 25 in

Radius of circle is equal to half of the diameter.

radius = \frac{diameter}{2}=\frac{25}{2}=12.5\ in

Now we know that the area of circle is equal to π times square of the radius.

framing in equation form, we get;

Area = \pi \times12.5^2

Now to find the part of the center to the whole target we will divide Area of center with Area of the target.

framing in equation form we get;

the part of the center to the whole target = \frac{\pi \times2.5^2}{\pi \times12.5^2}= \frac{6.25}{156.25} = \frac{1}{25}

Hence the center is \frac{1}{25} of the whole target.

6 0
3 years ago
(-72)/(-6)<br> Awnser <br> Plz&amp;Thx
KIM [24]
(-72)/(-6) equals to 12
8 0
3 years ago
Read 2 more answers
The archway of the main entrance of a university is modeled by the quadratic equation
Scilla [17]

Answer:

B. (1,5) and (5.25, 3.94)

Step-by-step explanation:

The answer is where the 2 equations intersect.

We need to solve the following system of equations:

y = -x^2 + 6x

4y = 21 - x

From the second equation:

x = 21 - 4y

Plug this into the first equation:

y = -(21 - 4y)^2 + 6(21 - 4y)

y = -(441 - 168y + 16y^2)+  126 - 24y

y = -441 + 168y - 16y^2 +  126 - 24y

16y^2 + y - 168y + 24y + 441 - 126 = 0

16y^2 - 143y + 315 = 0

y = [-(-143) +/- sqrt ((-143)^2 - 4 * 16 * 315)]/ (2*16)

y = 5, 3.938

When y = 5:

x = 21 - 4(5) = 1

When y = 3.938

x = 21 - 4(3.938) = 5.25.

3 0
3 years ago
Evaluate 6|8−y|−15 when y = 10
geniusboy [140]

Step-by-step explanation:

6|8-y|-15

6|8-10|-15

6|-2|-15

6(2)-15

12-15

-3

7 0
3 years ago
Your Numbers are; 25, 75, 50, 1, 9, 3 and your Target is 386 How do i get to 386 using only these numbers once and I can use Sub
GuDViN [60]

Answer:

You must order the operations  in the way that it unfolds in the explanation;:

Step-by-step explanation:

(25 x 9) +75 + 50+ 9 x ( 3 + 1)

When performing the operations we have the following results:

(25 x 9) =225 +75= 300+50 = 350+9 = 359 x (3+1 )

Now we must solve the following: 359 x (4) = 386

8 0
3 years ago
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