The mean of a set of normally distributed data is 600 with a standard devastation of 20. What percent of data is between 580 and
1 answer:
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Answer:
.
Step-by-step explanation:
5x + 3y = 26 (times 6) 30x + 18y = 156
6x + 7y = 21 (times 5) 30x + 35y = 105
.
30x + 18y = 156
<u>30x + 35y = 105 </u> <u> </u>
-17y = 51
y = -3
.
Substitute the value of y to one of equations
6x + 7y = 21
6x + 7(-3) = 21
6x - 21 = 21
6x = 21 + 21
6x = 42
x = 7
Answer:
Probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Step-by-step explanation:
We are given that the diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 millimeters.
<em>Firstly, Let X = diameters of ball bearings</em>
The z score probability distribution for is given by;
Z = ~ N(0,1)
where, = mean diameter = 106 millimeters
= standard deviation = 4 millimeter
Probability that the diameter of a selected bearing is greater than 111 millimeters is given by = P(X > 111 millimeters)
P(X > 111) = P( >
) = P(Z > 1.25) = 1 - P(Z
1.25)
= 1 - 0.89435 = 0.1056
Therefore, probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.