The mean of a set of normally distributed data is 600 with a standard devastation of 20. What percent of data is between 580 and
1 answer:
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Answer:
x
Step-by-step explanation:
Using the trigonometric identities
1 + tan²x = sec²x and 1 - sin²x = cos²x
secx =
Given
=
=
= cos²x × cos²x
= x
Answer:
tan (48°19'23'') => 1.1232
Step-by-step explanation:
60' minutes are present in a degree, and 60 * 60' seconds are present in a degree;
48°19'23'' = 48 + 19/60 + 23/3600
=
=
= = 48.323°
tan(48.323°) = 1.1232