There are two steps to this problem. The first step is to make an equation for the cost of each company. The cost of each one involves 2 variables. However, we can ignore the number of days since the question asks for per day.
CostA = 90 + .40(miles)
CostB = 30 + .70(miles)
We want to know when A is a better deal or when A costs less. That is when CostA < CostB. We can then substitute the right sides of our equations into the inequality. This will give:
90 + .40(miles) < 30 + .70(miles) This is where we will now begin to solve for the number of miles.
-30 -30 Subtract 30 from both sides.
60 + .4(miles) < .7(miles) Simplify
-.4(miles) -.4(miles) Subtract .4(miles) from both sides
60 < .3(miles) Simplify
/.3 /.3 Divide both sides by .3
200 < miles Simplify
So for A to cost less the number of miles must be greater than 200.
Answer:
WHERE IS THE TABLE
Step-by-step explanation:
Answer: Just drag each box over to the other box
Step-by-step explanation:
just how i said
Answer:
a
Step-by-step explanation:
One way to find the least common multiple of two numbers is to first list the prime factors of each number.
8 = 2 x 2 x 2
Then multiply each factor the greatest number of times it occurs in either number. If the same factor occurs more than once in both numbers, you multiply the factor the greatest number of times it occurs.
2: three occurrences
3: one occurrence
So, our LCM should be
2 x 2 x 2 x 3 = 24.
So, Marco can buy, at the very least, 24 beads of each color to have equal colors of beads.
