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Serhud [2]
3 years ago
11

PLEASE HELP STAT AND FILL IN THE BLANKS

Mathematics
1 answer:
Reil [10]3 years ago
4 0

Answer: So if Allison has 30 beads and each bracelet has 7. She would make 4 bracelets with 2 left over. The sentence would be If Alyson made 4 bracelets she would use 28 beads, leaving 2 left over.

Step-by-step explanation: 30/7 is 4 with a remainder of 2

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Someone plz help I don’t even know what this means
Vikentia [17]
What you wanna do here is use a calculator, as "e" in mathematics refers to the "e" on a calculator. The tricky part about this question is that the answer for the equation is the given percentage, NOT the value for "x". From there, plug in the multiple choice answers for "x" and see which one works!

In this case, A is the correct answer. B is absurdly large, so I omitted it immediately in the attached picture.

5 0
3 years ago
One third of a number Y
vampirchik [111]

Answer:

⅓y

Step-by-step explanation:

\frac{1}{3}  \times y \\  =  \frac{1}{3} y

4 0
3 years ago
Simplify the expression: –3(3 + 2n)
noname [10]

Answer:

-9 - 6n is the answer

8 0
3 years ago
Read 2 more answers
Jamal is making two paintings using canvases that are similar rectangles. The length of the smaller canvas is 3 ft and the width
Alex787 [66]
Let's start with what we know:

Smaller canvas:
Length (L_{1}) = 3ft
Width (W_{1}) = 5ft

Larger canvas:
Length (L_{2}) = ?
Width (W_{2}) = 10ft

Since these are similar rectangles, we can cross-multiply to calculate the missing length. Here's that formula:

\frac{ L_{1} }{ L_{2} } =  \frac{ W_{1} }{ W_{2} }
So let's plug it all in from above:

\frac{ 3 }{ L_{2} } = \frac{ 5 }{ 10 }
Now we cross multiply by multiplying the top-left by the bottom-right and vice versa:

(3)(10) = (5)(L_{2})
30 = 5L_{2}
Now divide each side by 5 to isolate L_{2}

\frac{30}{5} =  \frac{ 5L_{2}}{5}
The 5s on the right cancel out, leaving us with:

6 =  L_{2}

So the length of the larger canvas is 6 ft
4 0
3 years ago
Read 2 more answers
A certain substance doubles its volume every minute at 9 AM a small amount is placed in a container ,at 10 AM the container was
Y_Kistochka [10]

Answer:

the container is 1/4 full at 9:58 AM

Step-by-step explanation:

since the volume doubles every minute , the formula for calculating the volume V at any time t is

V(t)=V₀*2^-t , where t is in minutes back from 10 AM and V₀= container volume

thus for t=1 min (9:59 AM) the volume is V₁=V₀/2 (half of the initial one) , for t=2 (9:58 AM) is V₂=V₁/2=V₀/4  ...

therefore when the container is 1/4 full the volume is V=V₀/4 , thus replacing in the equation we obtain

V=V₀*2^-t

V₀/4 = V₀*2^-t

1/4 = 2^-t

appling logarithms

ln (1/4) = -t* ln 2

t = - ln (1/4)/ln 2 = ln 4 /ln 2 = 2*ln 2 / ln 2 = 2

thus t=2 min before 10 AM → 9:58 AM

therefore the container is 1/4 full at 9:58 AM

8 0
2 years ago
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