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Serhud [2]
3 years ago
11

PLEASE HELP STAT AND FILL IN THE BLANKS

Mathematics
1 answer:
Reil [10]3 years ago
4 0

Answer: So if Allison has 30 beads and each bracelet has 7. She would make 4 bracelets with 2 left over. The sentence would be If Alyson made 4 bracelets she would use 28 beads, leaving 2 left over.

Step-by-step explanation: 30/7 is 4 with a remainder of 2

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1.)A rectangle has an area of 72 square centimeters and the length is twice the width. The perimeter of the rectangle
Greeley [361]

1.

area = L x w = 72

L = 2w

72 = 2w*w = 2w^2

divide by 2

36 = w^2

w = sqrt(36) = 6 

l = 2*6 =12

perimeter = 2L +2W = 2*12 + 2*6 = 24+12 = 36


2.

sqrt(40)= 6.324555 cm ( round to 6.32 )

6.32 - 4 = 2.32 cm original length of a side


7 0
3 years ago
The GCF of 15 and 27 is _____.
jeka94

Answer:

The answer is 3

Step-by-step explanation:

List all prime factors

15:1,3,5,

27:1,3,

Biggest one is 3

8 0
2 years ago
Read 2 more answers
Factor completely. 10x^7-10xy^10
denis23 [38]
Find common factor, in this case the common factor is 10x
So the answer would be 10x(x^6 - y^10)


4 0
3 years ago
Please help I’ll give you brainlist or something
harkovskaia [24]

Answer:

1 slope of f is 5

slop of g is 2

2. connor

initial value is 200

rate of change is -10

Pilar

initial value is 242

rate of change is -8

3.

y intercept of f is -3

y intercept of g is -1

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Calculate the area of the triangle with the following vertices (3, -7), (6, 4), (-2, -3)
Monica [59]

Answer:

\boxed{\mathsf{A} \triangle = \red{\dfrac{67}{2}u.a}}

Step-by-step explanation:

Let's follow up with the solution. Considering a triangle with the vertices \mathsf{A(x_A, y_A)}, \mathsf{B(x_B, y_B)} and \mathsf{C(x_C, y_C)}, have a look at the representation in the cartesian plan.

From this representation we can say that the area (A) of a triangle through the knowledge of <u>analytical geometry</u> is given by the determinant of the vertices divided by two, mathematically,

\mathsf{A} \triangle =  \dfrac{\left| \begin{array}{ccc}  \mathsf{x_A} & \mathsf{y_A }& 1 \\  \mathsf{x_B} &  \mathsf{ y_B} & 1 \\ \mathsf{ x_C} &  \mathsf{ y_C} & 1 \end{array} \right|}{2}

So, applying this knowledge we're going to have,

\mathsf{A} \triangle =  \dfrac{\left| \begin{array}{ccc}  3 & -7 & 1 \\ 6 &  4 & 1 \\ -2 &  -3 & 1 \end{array} \right|}{2}

\mathsf{A} \triangle =  \dfrac{1}{2}\left[  \left.\begin{array}{ccc}   3 & -7 & 1 \\ 6 &  4 & 1 \\ -2&  -3 & 1 \end{array}  \right| \begin{array}{cc} 3 & -7 \\ 6 & 4 \\ -2 & -3 \end{array} \right]

\mathsf{A} \triangle = \dfrac{12 + 14 - 18 - (-8 - 9 - 42)}{2}

\red{\mathsf{A} \triangle = \dfrac{67}{2} = 33,5u.a}

Hope you enjoy it, see ya!)

\green{\mathsf{FROM}}: Mozambique, Maputo – Matola City – T-3

DavidJunior17

3 0
3 years ago
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