3 years ago

Need help with trig!

1 answer:

5 0

Answer:

1. A. $4.42$

2. F. $20.9$

3. G. $4.57$

4. A. $4.50$

Step-by-step explanation:

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timofeeve [1]

Answer: $\frac{2(y^2-4y+40)}{(y-8)(y+4)}$

Step-by-step explanation:

To solve this problem, we want to make sure the denominators are the same on both fractions. Once they are equal, we can dd them together.

$\frac{y+4}{y-8} +\frac{y-8}{y+4}$ [multiply first fraction by y+4 and second by y-8]

$\frac{(y+4)(y+4)}{(y-8)(y+4)} +\frac{(y-8)(y-8)}{(y-8)(y+4)}$ [distribute by FOIL]

$\frac{y^2+8y+16}{(y-8)(y+4)} +\frac{y^2-16y+64}{(y-8)(y+4)}$ [add numerator]

$\frac{y^2+8y+16+y^2-16y+64}{(y-8)(y+4)}$ [combine like terms]

$\frac{2y^2-8y+80}{(y-8)(y+4)}$ [factor out 2 from numerator]

$\frac{2(y^2-4y+40)}{(y-8)(y+4)}$

Now we know that $\frac{2(y^2-4y+40)}{(y-8)(y+4)}$ is the factored form after adding.

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3 years ago

bogdanovich [222]

X= 2 y=4 these are the intercepts

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3 years ago

tiny-mole [99]

Nvm

Step-by-step explanation:

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3 years ago

Natasha_Volkova [10]

2401 I had that question a few years ago

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4 years ago

maxonik [38]

Answer:

AD=7,BE=6,AB=4,AC=3.

3 0

3 years ago