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jasenka [17]
2 years ago
6

URGENT!! YOU WILL GET BRAINLIEST!

Mathematics
1 answer:
KiRa [710]2 years ago
4 0
Let Xo = original length of the deck
Yo = original width of deck
Therefore:
Yo = (1/6)Xo
The original deck area is:
Ao = XoYo
Ao = Xo(1/6)Xo = (1/6)Xo2
The length of the new deck is 4ft longer than the original deck, or XN = Xo + 4, and the width is 2ft longer than the original, or YN = Yo + 2, and the new area of the deck is 56ft2 than the original area, or AN = Ao + 56.
Therefore: AN = XNYN
Ao + 56 = (Xo + 4)(Yo + 2)
(1/6)Xo2 + 56 = (Xo + 4)(1/6Xo + 2)
(1/6)Xo2 + 56 = (1/6)Xo2 + 2Xo + (4/6)Xo +8
56 = 2Xo + (2/3)Xo +8
56 - 8 = (2 + 2/3)Xo
48 = (6/3 + 2/3)Xo
48 = (8/3)Xo
48(3/8) = Xo
Xo = 18ft
Yo = (1/6)(18)
Yo = 3ft
Check: Ao = XoYo = (18)(3) = 54ft2
XN = Xo + 4 = 18 + 4 = 22ft
YN = Yo + 2 = 3 + 2 = 5ft
AN = (22)(5) = 110ft2
Ao + 56 = AN
54 + 56 = 110
110 = 110 check------->ANSWER: original length, Xo = 18ft
original width, Yo = 3ft
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2 years ago
Axis of sym: x =
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Answer:

<h2>SEE BELOW</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • quadratic function
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<h3>let's solve:</h3>

vertex:(h,k)

therefore

vertex:(-1,4)

axis of symmetry:x=h

therefore

axis of symmetry:x=-1

  • to find the quadratic equation we need to figure out the vertex form of quadratic equation and then simply it to standard form i.e ax²+bx+c=0

vertex form of quadratic equation:

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therefore

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it's to notice that we don't know what a is

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3=a(0+1)²+4

simplify parentheses:

3 = a(1 {)}^{2}  + 4

simplify exponent:

3 =  a + 4

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a =  - 1

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let's simplify it to standard form

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simplify parentheses:

y =  -  {x}^{2}  - 2x - 1 + 4

simplify addition:

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the domain of the function

x\in \mathbb{R}

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factor out x and -1 respectively:

\sf \implies \: x(x + 3)   - 1(x  + 3 )= 0

group:

\implies \: (x - 1)(x + 3) = 0

therefore

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