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3 years ago

12

Scarlet open a savings account and deposited $100 as principal. The account earns 10% interest, compounded yearly. What is the b

alance after 9 years?

1 answer:

koban [17]3 years ago

5 0

Answer:

190

Step-by-step explanation:

100x10x9/100=90

balance=100+90=190

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The following three shapes are based only on squares, semicircles, and quarter circles. Find the perimeter and the area of each

zysi [14]

Answer:

Area: 16π-32

Perimeter: 4π + 8sqrt(2)

Step-by-step explanation:

Area:

The shaded part plus the right triangle BCD makes a quarter circle, so you can find the area of the quarter circle minus the triangle.

For the quarter circle, the radius is 8, so the entire circle area is 64π, making the quarter circle 16π.

The triangle is 8*8/2 = 32.

So, the quarter circle minus the triangle, or the area, is 16π-32.

Perimeter:

Again, this is a quarter circle. So, you can add the lengths of arc BD and the line segment BD.

The radius is 8, so the entire circumference is 16π, making the quarter circle 4π.

The hypotenuse of the right triangle will be sqrt(8*8+8*8), or 8sqrt(2).

Add and get 4π + 8sqrt(2) as your perimeter.

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3 years ago

MY LAST QUESTION<br><br> help me pleaseee<br><br> thankss

Brrunno [24]

Answer: there you go

Step-by-step explanation:

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3 years ago

Read 2 more answers

A concession stand vendor counts the money in the register. after 2 h it has $82.75. after 6 h is has $ 360.75. how much money w

Volgvan

I believe the answer would be c. $499.75. If you take (360.75-82.75)/(6-2) you get 278/4 which is dollars/hour, and that =69.5 so the rate of increase is $69.50 per hour, therefore if 6 hours produced $360.75 then you +$69.50•2(hours) and get $499.75

4 0

3 years ago

What sum will amount to rupees 4000 in 3 years at 6% p.a. compound interest

natali 33 [55]

Answer:

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{purple}{Given:}}}}}}}\end{gathered}$

⇢ Principle = Rs.4000
⇢ Rate = 6%
⇢ Time = 3 year

$\begin{gathered}\end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{purple}{To Find:}}}}}}}\end{gathered}$

⇢ Amount

$\begin{gathered}\end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{purple}{Using Formula:}}}}}}}\end{gathered}$

${\dag{\underline{\boxed{\sf{Amount ={P{\bigg(1 + \dfrac{R}{100}{\bigg)}^{T}}}}}}}}$

$\dag{\underline{\boxed{\sf{Compound \: Interest = Amount- Principle }}}}$

$\begin{gathered}\end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{purple}{Solution:}}}}}}}\end{gathered}$

${\bigstar \:{\underline{\pmb{\frak{\red{Firstly,Finding \: the \: Amount }}}}}}$

$\quad {:\implies{\sf{Amount = \bf{P{\bigg(1 + \dfrac{R}{100}{\bigg)}^{T}}}}}}$

Substituting the values

$\quad {:\implies{\sf{Amount = \bf{4000{\bigg(1 + \dfrac{6}{100}{\bigg)}^{3}}}}}}$

$\quad {:\implies{\sf{Amount = \bf{4000{\bigg(1 \times 100 + \dfrac{6}{100}{\bigg)}^{3}}}}}}$

$\quad {:\implies{\sf{Amount = \bf{4000{\bigg( \dfrac{100 + 6}{100}{\bigg)}^{3}}}}}}$

$\quad {:\implies{\sf{Amount = \bf{4000{\bigg( \dfrac{106}{100}{\bigg)}^{3}}}}}}$

$\quad {:\implies{\sf{Amount = \bf{4000{\bigg({\cancel{\dfrac{106}{100}}{\bigg)}}^{3}}}}}}$

$\quad {:\implies{\sf{Amount = \bf{4000{\bigg( \dfrac{53}{50}{\bigg)}^{3}}}}}}$

$\quad {:\implies{\sf{Amount = \bf{4000{\bigg( \dfrac{53}{50} \times \dfrac{53}{50} \times \dfrac{53}{50}{\bigg)}}}}}}$

$\quad {:\implies{\sf{Amount = \bf{4000{\bigg( \dfrac{148877}{125000}{\bigg)}}}}}}$

$\quad {:\implies{\sf{Amount = \bf{4000 \times \dfrac{148877}{125000}}}}}$

$\quad {:\implies{\sf{Amount = \bf{4{\cancel{000}} \times \dfrac{148877}{125{\cancel{000}}}}}}}$

$\quad {:\implies{\sf{Amount = \bf{\dfrac{148877 \times 4}{125}}}}}$

$\quad {:\implies{\sf{Amount = \bf{\dfrac{595508}{125}}}}}$

$\quad {:\implies{\sf{Amount = \bf{\cancel{\dfrac{595508}{125}}}}}}$

$\quad {:\implies{\sf{Amount = \bf{4764.064}}}}$

$\begin{gathered} \dag{\boxed{\textsf{\textbf{\underline{\color{green}{Amount = {Rs.4764.064}}}}}}}\end{gathered}$

Hence, The Amount is Rs.4764.064

$\begin{gathered}\end{gathered}$

${\bigstar \:{\underline{\pmb{\frak{\red{ Now,Finding \: The \: Compound \: Interest }}}}}}$

$\quad{: \implies{\sf{Compound \: Interest = \bf{Amount- Principle }}}}$

Substituting the values

$\quad{: \implies{\sf{Compound \: Interest = \bf{4764.064- 4000 }}}}$

$\quad{: \implies{\sf{Compound \: Interest =\bf{764.064}}}}$

$\begin{gathered} \dag{\boxed{\textsf{\textbf{\underline{\color{green}{Compound Interest = Rs.764.064}}}}}}\end{gathered}$

Henceforth,The Compound Interest is Rs.764064

$\begin{gathered}\end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{purple}{Learn More:}}}}}}}\end{gathered}$

$\begin{gathered}\begin{gathered}\begin{gathered} \dag \: \underline{\bf{More \: Useful \: Formula}}\\ {\boxed{\begin{array}{cc}\dashrightarrow {\sf{Amount = Principle + Interest}} \\ \\ \dashrightarrow \sf{ P=Amount - Interest }\\ \\ \dashrightarrow \sf{ S.I = \dfrac{P \times R \times T}{100}} \\ \\ \dashrightarrow \sf{P = \dfrac{Interest \times 100 }{Time \times Rate}} \\ \\ \dashrightarrow \sf{P = \dfrac{Amount\times 100 }{100 + (Time \times Rate)}} \\ \end{array}}}\end{gathered}\end{gathered}\end{gathered}$

8 0

3 years ago

The first discount on a camera was 18%. The second discount was 20%. After these two discounts the price was $328. What was the

Artyom0805 [142]

Answer:

$500

Step-by-step explanation:

We can find the original price of the camera through a proportion. A proportion is an equation where two ratios or fractions are equal. The ratios or fractions compare like quantities.

<u>Second Discount</u>

20% off means we paid 80%. We know we paid $328 of some price.

$\frac{80}{100} =\frac{328}{y}$

I can now cross-multiply by multiplying numerator and denominator from each ratio.

$80y=100(328)\\80y=32800$

I now solve for y by dividing by 80.

$\frac{80y}{80} =\frac{32800}{80} \\y= $410$

The price after the first discount was $410.

<u>First Discount</u>

We will repeat the steps above with $410. 18% off means we paid 82%.

$\frac{82}{100} =\frac{410}{y}$

I can now cross-multiply by multiplying numerator and denominator from each ratio.

$82y=100(410)\\82y=41000$

I now solve for y by dividing by 82.

$\frac{82y}{82} =\frac{41000}{82} \\y= $500$

The original price was $500.

5 0

3 years ago