GIVEN
The following values are given:
SOLUTION
The z-score for the x values 9 and 14 can be calculated using the formula:
For x = 9:
For x = 14:
The probability can be calculated as follows:
![P(9\le x\le14)=Pr(-0.34The region that represents the solution is shown below:Therefore, the probability is given to be:[tex]P(9\le x\le14)=0.4671](https://tex.z-dn.net/?f=P%289%5Cle%20x%5Cle14%29%3DPr%28-0.34The%20region%20that%20represents%20the%20solution%20is%20shown%20below%3A%3Cp%3ETherefore%2C%20the%20probability%20is%20given%20to%20be%3A%3C%2Fp%3E%5Btex%5DP%289%5Cle%20x%5Cle14%29%3D0.4671)
The probability is 0.4671.
Answer:
an = 1/2 (n) (n+1)
Step-by-step explanation:
1,3,6,10,.........
3-1=2
6-3=3
Each term is different so there is no common difference. It is not an arithmetic sequence
3/1=3
6/3 =2
Each term is different so there is no common ratio. It is not a geometric sequence
1 3 6 10
+2 +3 +4
a1 = 1
a2 = 3
a3 = 6 = 2*3
a4 = 10 = 2*5
Add all the chips to find the total amount.
7 + 9 + 3 + 6 = 25 chips
Since there are 6 blue chips (6/25), that's the probability of just getting once.
When you pick a blue chip and it doesn't get replaced, then that means there is one fewer blue chip and one fewer from the total amount.
5/24
Multiply both probabilities.
6/25 * 5/24 = 30/600
Simplify.
30/600 → 1/20
Therefore, the answer is B
Best of Luck!
Answer:
0.156
Step-by-step explanation:
Given that :
% of Explained variance by certain predictors of first year college grade :
SAT 11 scores = 17%
GPA = 15.6%
SAT 1 = 13.3%
Fitting a least squares line :
y = First year college GPA
x = high school GPA
THE r² value which is Coefficient of determination is the percentage of explained variance given by the regression line. The r² value of GPA will the as given above 15.6%
r² = 15.6% = 15.6/100 = 0.156
To find out the last operation, we must solve the entire problem.
We are given:
Let's simplify the signs so they don't clutter our equation.
We always need to be sure to use PEMDAS. Since there is no expression to solve in parenthesis and no exponents are present, we will move on to multiplication. We can multiply -9 and -6 in the denominator. When we do that, we get:
Next, all you need to do is combine like terms in the numerator and the denominator.
Simplify.
To answer the question, the last operation to be performed when finding the value would be division.
