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DiKsa [7]
2 years ago
5

After every eighth visit to a restaurant you receive a free beverage. After every tenth visit you receive a free appetizer. If y

ou visit the restaurant 100 times, on which visits will you receive a free beverage and a free appetizer? At which visit will you first receive a free beverage and a free appetizer? Drag and drop the correct value into each box to complete the statement. You will receive a free beverage and a free appetizer on the and visits, and you will first receive a free beverage and a free appetizer on the visit.
Mathematics
2 answers:
AleksandrR [38]2 years ago
8 0

Answer:

Step-by-step explanation:

Kaylis [27]2 years ago
4 0

Answer:

40th and 80th visit

the first visit where you receive both is the 40th

Step-by-step explanation:

personally, I believe that the simplest way to solve this is use an excel spreadsheet to see which visits would include both a free beverage and a free appetizer:

  • both rewards would happen only twice, at the 40th and 80th visit.

you can also calculate it mathematically since multiples of 8 and 10 do not repeat themselves very much, only when 8 is multiplied by 5 and 10.

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Abraham needs a total of 2 kg of flour to bake
kari74 [83]
So you need to divide 1000 by 125 which is 8. Which then you times by two to equal the two kilograms. So he needs to fill the cup up 16 times.
5 0
2 years ago
What is 5.316 - 1.942 btw (show ur work) :)
erastovalidia [21]

Answer:

3.374

Step-by-step explanation:

\mathrm{Write\:the\:numbers\:one\:under\:the\:other,\:line\:up\:the\:decimal\:points.}

\mathrm{Add\:trailing\:zeroes\:so\:the\:numbers\:have\:the\:same\:length.}

\begin{matrix}\:\:&5&.&3&1&6\\ -&1&.&9&4&2\end{matrix}

\mathrm{Subtract\:each\:column\:of\:digits,\:starting\:from\:the\:right\:and\:working\:left}

\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:6-2=4\\

\frac{\begin{matrix}\:\:&5&.&3&1&\textbf{6}\\ -&1&.&9&4&\textbf{2}\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&\:\:&\textbf{4}\end{matrix}}

\frac{\begin{matrix}\:\:&5&.&3&\textbf{1}&6\\ -&1&.&9&\textbf{4}&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&\textbf{\:\:}&4\end{matrix}}

\frac{\begin{matrix}\:\:&5&.&\textbf{3}&1&6\\ -&1&.&\textbf{9}&4&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\textbf{\:\:}&\:\:&4\end{matrix}}

\frac{\begin{matrix}\:\:&\textbf{4}&\:\:&10&\:\:&\:\:\\ \:\:&\textbf{\linethrough{5}}&.&3&1&6\\ -&\textbf{1}&.&9&4&2\end{matrix}}{\begin{matrix}\:\:&\textbf{\:\:}&\:\:&\:\:&\:\:&4\end{matrix}}\\

\frac{\begin{matrix}\:\:&4&\:\:&\textbf{13}&\:\:&\:\:\\ \:\:&\linethrough{5}&.&\textbf{\linethrough{3}}&1&6\\ -&1&.&\textbf{9}&4&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\textbf{\:\:}&\:\:&4\end{matrix}}

\frac{\begin{matrix}\:\:&4&\:\:&\textbf{12}&10&\:\:\\ \:\:&\linethrough{5}&.&\textbf{\linethrough{13}}&1&6\\ -&1&.&\textbf{9}&4&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\textbf{\:\:}&\:\:&4\end{matrix}}

\frac{\begin{matrix}\:\:&4&\:\:&12&\textbf{11}&\:\:\\ \:\:&\linethrough{5}&.&\linethrough{13}&\textbf{\linethrough{1}}&6\\ -&1&.&9&\textbf{4}&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&\textbf{\:\:}&4\end{matrix}}

\frac{\begin{matrix}\:\:&4&\:\:&12&\textbf{11}&\:\:\\ \:\:&\linethrough{5}&.&\linethrough{13}&\textbf{\linethrough{1}}&6\\ -&1&.&9&\textbf{4}&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&\textbf{7}&4\end{matrix}}

\frac{\begin{matrix}\:\:&4&\:\:&\textbf{12}&11&\:\:\\ \:\:&\linethrough{5}&.&\textbf{\linethrough{13}}&\linethrough{1}&6\\ -&1&.&\textbf{9}&4&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\textbf{3}&7&4\end{matrix}}

\frac{\begin{matrix}\:\:&4&\textbf{\:\:}&12&11&\:\:\\ \:\:&\linethrough{5}&\textbf{.}&\linethrough{13}&\linethrough{1}&6\\ -&1&\textbf{.}&9&4&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\textbf{.}&3&7&4\end{matrix}}

\frac{\begin{matrix}\:\:&\textbf{4}&\:\:&12&11&\:\:\\ \:\:&\textbf{\linethrough{5}}&.&\linethrough{13}&\linethrough{1}&6\\ -&\textbf{1}&.&9&4&2\end{matrix}}{\begin{matrix}\:\:&\textbf{3}&.&3&7&4\end{matrix}}

=3.374

6 0
1 year ago
Please answer for branliest
Lostsunrise [7]

Answer:

50%

Step-by-step explanation:

There are 2 cards greater than 5 , that is 6 and 7 , then

P( greater than 5 ) = \frac{2}{4} = \frac{1}{2} = 50%

4 0
2 years ago
Please help please I don’t know :( explain please
Bas_tet [7]

Answer:

t = 5

Step-by-step explanation:

It's asking what t needs to equal for the equation to be equivalent to -44.

-10t + 6 = -44

-10t = -50

t = 5

check

-10(5) + 6 = -44

-50 + 6 = -44

-44 = -44

3 0
2 years ago
Read 2 more answers
Help. please read the instructions and Answer the questions​
Dominik [7]

9514 1404 393

Explanation:

We refer to the equations as [1] and [2]. We refer to the items as (1) – (4).

__

1. The terms to be eliminated have matching coefficients in (1) and (2). They can be eliminated by subtracting one equation from the other.

In (3) and (4), putting the equations in standard form* results in terms with opposite coefficients. Those terms can be eliminated by adding the equations.

__

2. Terms to be eliminated will have matching or opposite coefficients.

__

3. In (1) and (2), the variable x can be eliminated by subtracting one equation from the other. In the attachment, we have indicated the subtraction that will result in the remaining variable having a positive coefficient.

__

4. In (3) and (4), the coefficients of the variables are not equal or opposite in the two equations, so no variable can be eliminated directly.

__

5. As suggested by the answer to Q4, an equivalent equation must be found that has an equal or opposite variable coefficient with respect to the other equation. The new equations are ...

  (3) [2] ⇒ x -y = 2

  (4) [1] ⇒ 2x +2y = 3

_____

Here are the solutions:

(1) [1] -[2]  ⇒  (x +y) -(x -y) = (-1) -(3)

  2y = -4  ⇒  y = -2

  x = y +3 = 1 . . . . from [2]

  (x, y) = (1, -2)

__

(2) [2] -[1]  ⇒  (x +2y) -(x +y) = (8) -(5)

  y = 3

  x = 5 -y = 2 . . . . from [1]

  (x, y) = (2, 3)

__

(3) [1] +[2]/2  ⇒  (x +y) +(x -y) = (1) +(2)

  2x = 3  ⇒  x = 3/2

  y = 1 -x = -1/2 . . . . from [1]

  (x, y) = (3/2, -1/2)

__

(4) [2] +[1]/2  ⇒  (5x -2y) +(2x +2y) = (4) +(3)

  7x = 7  ⇒  x = 1

  y = (3 -2x)/2 = 1/2

  (x, y) = (1, 1/2)

_____

* Equations in standard form have mutually prime coefficients. In (3) a factor of 2 can be removed from equation [2]. In (4), a factor of 2 can be removed from equation [1].

7 0
2 years ago
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