GIVEN :
a = 1/√10 ( 3i + k) and
b = 1/7 ( 2i + 3j - 6k)
TO FIND :
( 2a- b) . [ ( a x b ) x ( a + 2b)]
SOLUTION :
◆Going with the equation given,
( 2a - b) . [ ( a x b ) x ( a + 2b)]
= (2a - b) [( a×b×a) + 2(a×b)×b]
◆BAC - CAB RULE,
A×B×C = B( A.B ) - C(A.B )
= (2a- b ) [ (b (a.a ) - a (a.b ) + 2b ( a.b) -2b (a.b]
Solving further
= (2a - b )(b - 2a)
= -4a.a -b.b
=-5.
Answer:
( 2 - b) . [ ( a x b ) x ( a + 2b)] = -5
Hoped I helped
The answer is 4.
The reason is that 5 times 4 is 20.
Assuming the shape is a piece of a circle, you can determine the ratio of the shape to a full circle. A full circle will have 360 degree but this shape is only 40 degree. Then the ratio would be: 40/360= 1/9 full circle.
Then, using the circle area formula, the area of the 1/9 circle would be:
full circle area= pi * r^2
full circle area= 22/7 * 6^2
full circle area= 792/7
1/9 full circle area= 792/7*9= 88/7 = 12.57
Answer:
Since zero has no value, it does not need to be included when writing a number in expanded form.
Step-by-step explanation:
Answer:
I think its a,c,d,f, and g
