Answer:
<h3>your question :</h3>
how to rapidly separate red#40 from ZnO
<h3>answer :</h3>
Red #40 is soluble in water while zinc oxide is not. 4- heat the solution of red #40 and water until water evaporates and red#40 remains
hope it's help
<h3>#carryONlearning </h3>
Explanation:
Formula to calculate standard electrode potential is as follows.
= 0.535 - 1.065
= - 0.53 V
Also, it is known that relation between and K is as follows.
ln K =
Substituting the given values into the above formula as follows.
ln K =
=
ln K = -41.28
K =
=
Thus, we can conclude that the value of the equilibrium constant for the given reaction is .
So, Ba is divalent. This means that each Ba(OH)2 requires two I in order to produce one BaI2 molecule.
The two hydrogens from the 2 HI molecules will combine with 2 OH of Ba(OH)2 forming 2 water (H2O) molecules.
The equation which illustrates this reaction in as follows:
<span>2 HI (aq) + Ba(OH)2 (s) ........> BaI2 (aq) + 2 H2O (l)
</span>where:
aq refers to aqueous state
s refers to solid state and
l refers to liquid state.
Answer:
- 5.15×10²⁴ molecules of sulfur dioxide
- 3.63×10²³ molecules of carbon monoxide
- 6.02×10²³ molecules of ammonia
Explanation:
We begin from the relation that 1 mol of molecules contains NA of molecules
NA = 6.02×10²³
Now, we make rules of three:
1 mol has 6.02×10²³ molecules, therefore:
8.55 moles of SO₂ must have (8.55 . NA) / 1 = 5.15×10²⁴ molecules of dioxide
0.603 moles of CO must have (0.603 . NA) / 1 = 3.63×10²³ molecules of monoxide
Avogadro's Number of molecules of NH₃ are 6.02×10²³ molecules of ammonia