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Pepsi [2]
2 years ago
11

The number of employees at a certain company is 1440 and is increasing at a rate of 1.5% per year. Write an exponential growth f

unction to model this situation. Then find the number of employees in the company after 9 years
Mathematics
1 answer:
stealth61 [152]2 years ago
8 0
1.5% of 1440 is 21.6 and in nine years they will have 13.5 +1440 is 1453.5
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From the lighthouse 1000 ft above sea level the angle of depression to boat a is 29 degress.a little bit later the boat moved cl
AnnyKZ [126]

Answer: The boat moved 768.51 feet  in that time .

Step-by-step explanation:

Since we have given that

Height of the lighthouse = 1000 feet

Angle depression to boat 'a' = 29°

Angle of depression  to shore 'b' = 44°

Consider ΔABC,

\tan 44\textdegree=\frac{AB}{BC}\\\\\tan 44\textdegree=\frac{1000}{BC}\\\\BC=\frac{1000}{\tan 44\textdegree}\\\\BC=1035.53\ feet

Now, Consider, ΔABD,

\tan 29\textdegree=\frac{AB}{BD}\\\\\tan 29\textdegree=\frac{1000}{BD}\\\\BD=\frac{1000}{\tan 29\textdegree}\\\\BD=1804.04\ feet

We need to find the distance that the boat moved in that time i.e. BC

so,

DC=BD-BC\\\\CD=1804.04-1035.53\\\\CD=768.51\ feet

Hence, the boat moved 768.51 feet  in that time .

6 0
3 years ago
-52.5 as a mixed number
Thepotemich [5.8K]

-52 and 1/2


Ik its late

3 0
3 years ago
Pls help!! 5star and brainliest
Kazeer [188]

Answer:

C, A, C

Hope This Helps!

6 0
3 years ago
65 traffic cones we’re equally spaced over 5/8 of a mile how many traffic cones are used per mile
Paha777 [63]

Given:

65 traffic cones we’re equally spaced over \dfrac{5}{8} of a mile.

To find:

The number of traffic cones are used per mile.

Solution:

We have,

Number of cones used in \dfrac{5}{8} of a mile = 65

Number of cones used for a mile = 65\times \dfrac{8}{5}

                                                       = 13\times 8

                                                       = 104

Therefore, 104 traffic cones are used per mile.

8 0
2 years ago
Just a quick question:
Vinvika [58]

You need to subtract the rate of decay from 1.

The equation would be 800(1-0.2)^x = 800(0.80)^x

4 0
2 years ago
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