Find the measure of the missing angel

Identify the word form of this number: 139,204,539,912

Naya [18.7K]

One hundred thirty-nine billion, two hundred four million, five hundred thirty-nine thousand, nine hundred twelve.

Hope this helped!

5 0

2 years ago

Which expression is equal to

melamori03 [73]

Answer:

D is the most acurate answer.

Step-by-step explanation:

8 0

2 years ago

Assume that 155 students are surveyed and every student takes at least one of the following languages. The results of the survey

balu736 [363]

Answer:

91 people take Russian

26 people take French and Russian but not German

Step-by-step explanation:

To solve this problem, we must build the Venn's Diagram of this set.

I am going to say that:

-The set A represents the students that take French.

-The set B represents the students that take German

-The set C represents the students that take Russian.

We have that:

$A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)$

In which a is the number of students that take only Franch, A \cap B is the number of students that take both French and German , A \cap C is the number of students that take both French and Russian and A \cap B \cap C is the number of students that take French, German and Russian.

By the same logic, we have:

$B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)$

$C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)$

This diagram has the following subsets:

$a,b,c,(A \cap B), (A \cap C), (B \cap C), (A \cap B \cap C)$

There are 155 people in my school. This means that:

$a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 155$

The problem states that:

90 take Franch, so:

$A = 90$

83 take German, so:

$B = 83$

22 take French, Russian, and German, so:

$A \cap B \cap C = 22$

42 take French and German, so:

$A \cap B = 42 - (A \cap B \cap C) = 42 - 22 = 20$

41 take German and Russian, so:

$B \cap C = 41 - (A \cap B \cap C) = 41 - 22 = 19$

22 take French as their only foreign language, so:

$a = 22$

Solution:

(1) How many take Russian?

$C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)$

$C = c + (A \cap C) + 19 + 22$

$C = c + (A \cap C) + 41$

First we need to find $A \cap C$ , that is the number of students that take French and Russian but not German. For this, we have to go to the following equation: