The measures of two complementary angles are 64 degrees and 26 degrees
<h3><u>Solution:</u></h3>
Let the larger angle be "a" and smaller angle be "b"
<em>Two angles are Complementary when they add up to 90 degrees</em>
so we get,
a + b = 90 ------ eqn 1
Given that measure of the larger angle is 12 more than twice the measure of the smaller angle
larger angle = 12 + 2(smaller angle)
a = 12 + 2b --- eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to get values of "a" and "b"</u></em>
Substitute eqn 2 in eqn 1
12 + 2b + b = 90
12 + 3b = 90
3b = 90 - 12
3b = 78
<h3>b = 26</h3>
Therefore from eqn 2,
a = 12 + 2b
a = 12 + 2(26)
a = 12 + 52
<h3>a = 64</h3>
Thus the measures of two complementary angles are 64 degrees and 26 degrees
Answer:
Therefore,
The area of the sector is 15.09 unit².
Step-by-step explanation:
Given:
Circle with,
radius = r = 6 unit
central angle = θ = 48°
pi = 3.143
To Find:
Area of sector = ?
Solution:
If 'θ' is in degree the area of sector is given as

Substituting the values we get

rounded to nearest hundredth
Therefore,
The area of the sector is 15.09 unit².
Answer:
16=x
Step-by-step explanation:
So, The angle is 180 degrees
180-87=93
93=(6x-3)
Add 3 to both sides
96=6x
Divide 6 on both sides
16=x
Answer:
31.
Step-by-step explanation:
1. Write out the problem.
6w-19 + k; w=8 and k=2
2. Figure out the first part of the problem.
So, if w=8 and 6 and w are next to each other, we should multiply 6*8, which is 48. Next, it says to subtract 19. 48-19=29.
3. Find out what the last part of the problem is.
Since the first part of the problem is 29 and k=2, we should add 29+2=31, which is the final answer.
Hope this helped :)