For this case we must indicate an expression equivalent to:
![(x ^ {\frac {1} {4}} * y ^ {16}) ^ {\frac {1} {2}}](https://tex.z-dn.net/?f=%28x%20%5E%20%7B%5Cfrac%20%7B1%7D%20%7B4%7D%7D%20%2A%20y%20%5E%20%7B16%7D%29%20%5E%20%7B%5Cfrac%20%7B1%7D%20%7B2%7D%7D)
By definition of power properties we have:
![(a ^ m) ^ n = a ^ {m * n}](https://tex.z-dn.net/?f=%28a%20%5E%20m%29%20%5E%20n%20%3D%20a%20%5E%20%7Bm%20%2A%20n%7D)
We can rewrite the expression as:
![((x ^ {\frac {1} {4}}) ^ {\frac {1} {2}}) * ((y ^ {16}) ^ {\frac {1} {2}}) =\\x ^ {\frac {1} {8}} * y ^ 8](https://tex.z-dn.net/?f=%28%28x%20%5E%20%7B%5Cfrac%20%7B1%7D%20%7B4%7D%7D%29%20%5E%20%7B%5Cfrac%20%7B1%7D%20%7B2%7D%7D%29%20%2A%20%28%28y%20%5E%20%7B16%7D%29%20%5E%20%7B%5Cfrac%20%7B1%7D%20%7B2%7D%7D%29%20%3D%5C%5Cx%20%5E%20%7B%5Cfrac%20%7B1%7D%20%7B8%7D%7D%20%2A%20y%20%5E%208)
Answer:
![x ^ {\frac {1} {8}} * y ^ 8](https://tex.z-dn.net/?f=x%20%5E%20%7B%5Cfrac%20%7B1%7D%20%7B8%7D%7D%20%2A%20y%20%5E%208)
You will need to divide 8 and 6. You should then get your answer.
Your constant is 3 because it’s alone
Answer:
Step-by-step explanation:
https://web.gccaz.edu/~johwd63181/MAT142/chapter_1/solutions/section%201.4%20solutions.pdf
Answer:
the greatest possible value for x is 6
Explanation:
Assume that the sides of the triangle are:
a = x
b = 3x
c = 20
We are given that c is the longest side.
For the triangle to be obtuse:
c^2 > a^2 + b^2
Substitute with the values of a, b and c and solve for x as follows:
c^2 > a^2 + b^2
(20)^2 > (x)^2 + (3x)^2
400 > x^2 + 9x^2
400 > 10 x^2
40 > x^2
Now, we will get the zeros of the function. This means that we will solve for x^2 = 40 as follows:
x^2 = 40
x = + or - √40
either x = 6.32
Or x = -6.32
Since we want x^2 < 40, therefore, the greatest possible value for x to satisfy this condition is 6
Hope this helps :)