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andrey2020 [161]
3 years ago
9

This is a lot but please help me I’ll mark u as brilliant

Mathematics
1 answer:
givi [52]3 years ago
7 0

Answer:

see below

Step-by-step explanation:

2:

# of sides = 3

# of vertices = 3

name of shape: triangle

3.

# of sides = 4

# of vertices = 4

name of shape: quadrilateral

4.

# of sides = 5

# of vertices = 5

name of shape: pentagon

5.

# of sides = 6

# of vertices = 6

name of shape: hexagon

6.

# of sides = 8

# of vertices = 8

name of shape: octagon

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To solve/simplify this all you have to do is group like terms (the x^2's with each other, the x's with each other, and the normal numbers, -8)

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3 years ago
Keenan will run 2.5 miles from his house to Jared’s house. He plans to hang out for 45 minutes before walking home. If he can ru
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Answer:

Kennan will be from home approximately an hour and 48 minutes.

Step-by-step explanation:

We must know that total time (t_{T}) that Keenan will be from home is the sum of run (t_{R}), hang out (t_{H}) and walk times (t_{W}), measured in hours:

t_{T} = t_{R}+t_{H}+t_{W}

If Keenan runs and walks at constant speed, then equation above can be expanded:

t_{T} = \frac{x_{R}}{v_{R}}+t_{H}+ \frac{x_{W}}{v_{W}}

Where:

x_{R}, x_{W} - Run and walk distances, measured in miles.

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t_{T} = \frac{2.5\,mi}{6\,\frac{mi}{h} } + 0.75\,h+\frac{2.5\,mi}{4\,\frac{mi}{h} }

t_{T} = 1.792\,h (1\,h\,48\,m)

Kennan will be from home approximately an hour and 48 minutes.

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