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Dmitry [639]
3 years ago
11

Three cylinders have a volume of 2826 cm. Cylinder A has a height of 900 cm. Cylinder B

Mathematics
1 answer:
makkiz [27]3 years ago
5 0

Answer:

the radius of each cylinder is 1 cm, 2 cm and 3 cm respectively

Step-by-step explanation:

The computation of the radius of each cylinder is shown below:

As we know that

The Volume of the cylinder = πr^2h

The radius would be

=\sqrt{  \frac{V}{\pi h} }

For cylinder A

=\sqrt{\frac{2826}{3.14\times 900} }

= 1 cm

For cylinder B

=\sqrt{\frac{2826}{3.14\times 225} }

= 2 cm

For cylinder C

=\sqrt{\frac{2826}{3.14\times 100} }

= 3 cm

Hence, the radius of each cylinder is 1 cm, 2 cm and 3 cm respectively

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The radius is 1.5 feet, and the height is 1.75 feet. What is h
Ksivusya [100]

Answer:

12.36 ft^3

Step-by-step explanation:

Volume of cylinder=πr²*h

3.14*1.5²=7.065

7.065*1.75=12.36ft^3

6 0
3 years ago
Read 2 more answers
You randomly choose an undergraduate student from a large state university. Let E be the event that the student is male, let F b
erik [133]

Answer:

( a ) is the right answer .

Step-by-step explanation:

P(E) = 0.48

Probability of being male = .48

Probability of being female = .52

P(F) = 0.72

Probability of being in state  = .72

Probability of being out of state  = .28

P(G) = 0.55

Probability of being in at least 20 years   = .55

Probability of being less than 20  = .45

a )

P(student is an in-state male younger than 20)

= .72 x .48 x .45 = .1555 = .156

b )

P(student is an out-of-state female younger than 20)

= .28 x .52 x .45

= .065

c )

P(student is an in-state female younger than 20)

= .72 x .52 x .45 = .168

d )

P(student is an out-of-state male at least 20)

= .28 x .48 x .55 = .074

So , ( a ) is the right answer .

3 0
4 years ago
Need help please I would be grateful
Xelga [282]

Answer:

The correct answer is given by option A.

Step-by-step explanation:

A function is said to be increasing for intervals of x in which the values of y are increasing, that is, it trends upwards, and decreasing for intervals of x in which the values of y are decreasing, that is, it trends downwards.

In this question:

It trends upwards from the start, at negative infinity, until 0.

It trends downwards from 0, until the end, at positive infinity.

So the correct answer is given by option A.

7 0
3 years ago
Consider the system of equations. y = −2x + 4 y = − 1/3x − 1
ipn [44]

Hey there! I'm happy to help!

We have two values for y. Since y=y, this means that −2x + 4 and − 1/3x − 1 are equal as well, so we can put them in an equation and solve for x.

−2x + 4 = − 1/3x − 1

We subtract 4 from both sides.

-2x=-1/3x-5

We add 1/3 x to both sides.

-5/3x=-5

We divide both sides by -1 2/3.

x=3

Now, we plug this into one of the original equations to find y.

y=-2(3)+4

y=-6+4

y=-2

Therefore, the solution is (3,-2) or x=3 and y=-2.

I hope that this helps! Have a wonderful day! :D

4 0
3 years ago
Solve the equation for x: 4 + 3 (x + 2) = -8<br><br> 6<br> -6<br> 2/3<br> -2/3
tankabanditka [31]

Answer:

x = -6

Step-by-step explanation:

4 + 3 (x + 2) = -8

Distribute the 3

4 +3x+6=-8

Combine like terms

10+3x=-8

Subtract 10 from each side

10-10+3x = -8-10

3x=-18

divide by 3 on both sides

3x/3 = -18x/3

x = -6

7 0
3 years ago
Read 2 more answers
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