Please help and get points!

At the beginning of a snowstorm, Grayson had 10 inches of snow on his lawn. The snow then began to fall at a constant rate of 0.

maxonik [38]

Answer:

Grayson had 10 inches of snow in his lawn
the snow falls at a constant rate of 0.5 inches per hour
no snow was melting
the snow has fallen for 3 hours

Let y be the height of the snow in the lawn

Grayson had 10 inches at the beginning (at t=0) so y= 10

3 hours passed so y= 10 + 3*0.5 = 11.5 inches

Grayson had 11.5 inches after three hours

Assuming that the snow continued to fall for an unkhown time t

y = 0.5*t + 10

we had 10 at the beginning so we add 10 (+10)

the snow is growing by 0.5 inches in the single hour so we multiply by 0.5

t is the time and it can 4, 5, 6 ...... hours

Just like a function :

0.5 is the slope
t is the variable
10 is the y-intercept

3 0

3 years ago

Based on the triangles, which statement is true?

AlladinOne [14]

The sum of interior angles of a triangle is 180°, and a linear pair is supplementary (adds to 180°). The appropriate choice is

... G. w = 105°, because ...

_____

In short, an exterior angle is equal to the sum of the opposite interior angles.

... w = 180 - (180 - (45 + 60)) = 180 -180 +45 +60

... w = 45 +60

4 0

3 years ago

You throw a ball up and its height h can be tracked using the equation h=2x^2-12x+20.

postnew [5]

This problem seems to be wrong because no minimum point was found and no point of landing exists

Answer:

1) There is no maximum height

2) The ball will never land

Step-by-step explanation:

Derivatives

Sometimes we need to find the maximum or minimum value of a function in a given interval. The derivative is a very handy tool for this task. We only have to compute the first derivative f' and have it equal to 0. That will give us the critical points.

Then, compute the second derivative f'' and evaluate the critical points in there. The criteria establish that

If f''(a) is positive, then x=a is a minimum

If f''(a) is negative, then x=a is a maximum

1)

The function provided in the question is

$h(x)=2x^2-12x+20$

Let's find the first derivative

$h'(x)=4x-12$

solving h'=0:

$4x-12=0$

x=3

Computing h''

h''(x)=4

It means that no matter the value of x, the second derivative is always positive, so x=3 is a minimum. The function doesn't have a local maximum or the ball will never reach a maximum height

2)

To find when will the ball land, we set h=0

$2x^2-12x+20=0$