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omeli [17]
3 years ago
9

To which character in Seedfolks does Paul Fleischman assign the most personal perspective on gardening?

Mathematics
2 answers:
Vsevolod [243]3 years ago
7 0

Answer:

i think its kim

Step-by-step explanation:

erastova [34]3 years ago
3 0

Answer: Kim

Step-by-step explanation:

  • Kim the first person to plant seeds in the vacant lot.
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Someone please help me
Natali [406]
62.8 is the correct answer. Hope this helps
4 0
3 years ago
Sarah took the advertising department from her company on a round trip to meet with a potential client. Including Sarah a total
patriot [66]

Sarah buys 4 first class tickets ad 9 coach tickets For the trip.

<h3>Equation</h3>

Equation is an expression which is used to show the relationship between two or more variables and numbers.

Let x represent the number of first class ticket and y represent the boxes of coach tickets

Sarah a total of 13 people took the trip. Hence:

  • x + y = 13   (1)

She used her total budget  which was $10,970. Hence:

  • 380x - 1050y = 10970    (2)

Solving equations 1 and 2 simultaneously gives:

x = 4, y = 9

Sarah buys 4 first class tickets ad 9 coach tickets For the trip.

Find out more on equation at: brainly.com/question/13763238

8 0
3 years ago
Can someone help me on this problem
seropon [69]
4 3/8 I think that is correct.
5 0
3 years ago
Write the equation of a line perpendicular to y=-2x+1 through (2,3) in slope intercept form.
Fed [463]

Answer:

y=\dfrac{1}{2}x+2

Step-by-step explanation:

y= - 2x + 1

Compare with y = mx + b

m = Slope = -2

Slope of the perpendicular line = -1/m = -1/-2 = 1/2

Point (2,3)

Equation : y -y1 =m(x -x1)

y - 3 = \dfrac{1}{2}*(x - 2)\\\\\\y-3=\dfrac{1}{2}*x - 2*\dfrac{1}{2}\\\\\\y -3=\dfrac{1}{2}x-1\\\\y =\dfrac{1}{2}x-1+3\\\\y=\dfrac{1}{2}x+2

7 0
3 years ago
What is this equation, equivalent to c(x)=(x+6)^2+14
Digiron [165]
<h3>Answer:  x^2+12x+50</h3>

Work Shown:

c(x) = (x+6)^2+14

c(x) = (x+6)(x+6)+14

c(x) = x(x+6)+6(x+6)+14

c(x) = x^2+6x+6x+36+14

c(x) = x^2+12x+50

7 0
4 years ago
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