M or the slope has to be constant throughout the graph. This is because in order for a line to be linear it has to be increasing or decreasing at the same rate. So it the slope was 2 from point x 1 -2 then the slope changed to 1 from 3-4 it would not be linear. :)
Answer:
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2 Answers: Choice B and Choice C
The rate of change is 2.
The rate of change is constant.
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Explanation:
The first point on the left is when x = 1.5 and it has a height of y = 1
The point (1.5, 1) is on the line.
So is the point (3,4) for similar reasoning.
Compute the slope between those points
m = (y2-y1)/(x2-x1)
m = (4-1)/(3-1.5)
m = 3/(1.5)
m = 2
The slope is 2, which is the same as saying the rate of change is 2. This only applies when x > 1 of which the interval 1.5 ≤ x ≤ 3 is a part of.
Since the slope stays at 2 on the interval 1.5 ≤ x ≤ 3, this means we consider the slope to be constant. If the curve bended at all on this interval, then it wouldn't be a constant slope.
We know that
the slope formula is
m=(y2-y1)/(x2-x1)
(x1,y1)=(0,2)
(x2,y2)=(x,0)
m=1-----> equation 1
m=(0-2)/(x-0)------> m=-2/x -----> equation 2
equate equation 1 and equation 2
1=-2/x------> multiply by x both sides------> x=-2
the point (x2,y2) is ----------> (-2,0)
Compounded depreciation formula:
A = P(1 - r)ⁿ , where P = original price, r= rate of depreciation, n = number of years and A = actual value (after depreciation):
A= $8000(1 - 11%)⁵ = 8000(0.89)⁵ = 4,467.24 ≈$4,467
