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madreJ [45]
3 years ago
11

I Need help with this please it’s Algebra and it’s 6 days late

Mathematics
1 answer:
Gnom [1K]3 years ago
5 0
1. (x+8)(x-5)
3. 15.2
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HELP PLEASE !!!!!!!!!!!!!!!!!!!!!!!!The coordinate of point A is -7 and the coordinate of point D is -2.
Marta_Voda [28]

Answer:

So we can first use the distance formula which is for 2 dimensional but seen as we're in 1 dimensions we dont have to use it. So we can just get the distance between them using a formula I made -

|a-d| = distance

So if we use that formula we can get that -7-(-2) = -7+2 = -5. Then take the absolute value which is 5.

Therefore the answer is

<h2><u>5 is answer</u></h2>

8 0
4 years ago
X
LekaFEV [45]
3(3+2)=12+3
3*5=15
15=15
He is correct
6 0
3 years ago
What is radiant energy from the sun called
Marrrta [24]
All of the energy from the Sun that reaches the Earth arrives as solar radiation, part of a large collection of energy called the electromagnetic radiation spectrum. Solar radiation includes visible light, ultraviolet light, infrared, radio waves, X-rays, and gamma rays.
3 0
3 years ago
Read 2 more answers
These expressions below represent four numbers. The value of the median of these expressions is 12.
Airida [17]

Answer:

The mean is 15

Explanation:

The x value that would get a median of 12 is three, which when taken the mean of the numbers when x is three, you get 15

6 0
3 years ago
Use stokes' theorem to evaluate c f · dr where c is oriented counterclockwise as viewed from above. f(x, y, z = xyi + 5zj + 7yk,
Helga [31]
The intersection can be parameterized by

C:=\mathbf r(t)=\begin{cases}x(t)=6\cos t\\y(t)=6\sin t\\z(t)=5-6\cos t\end{cases}

with 0\le t.

By Stoke's theorem, the integral of \mathbf f(x,y,z)=xy\,\mathbf i+5z\,\mathbf j+7y\,\mathbf k along C is equivalent to

\displaystyle\int_C\mathbf f(x(t),y(t),z(t))\cdot\mathrm d\mathbf r(t)=\iint_S\nabla\times\mathbf f\,\mathrm dS

where S is the region bounded by C. The line integral reduces to

\displaystyle\int_0^{2\pi}(36\sin t\cos t\,\mathbf i+(25-30\cos t)\,\mathbf j+42\sin t\,\mathbf k)\cdot(-6\sin t\,\mathbf i+6\cos t\,\mathbf j+6\sin t\,\mathbf k)\,\mathrm dt
=\displaystyle\int_0^{2\pi}(54(\cos3t-\cos t)-30(3\cos2t-5\cos t+3)+(126-126\cos2t)\,\mathrm dt
=\displaystyle\int_0^{2\pi}(36+96\cos t-216\cos2t+54\cos3t)\,\mathrm dt
=72\pi
4 0
4 years ago
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