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tia_tia [17]
3 years ago
5

A company models its net income, in thousands of dollars, with

Mathematics
1 answer:
pychu [463]3 years ago
8 0

Answer:

-15

Step-by-step explanation:

0)(2)+(2)(0)−15

=−15

You might be interested in
Compute the number of ways to deal each of the following five-card hands in poker. 1. Straight: the values of the cards form a s
Elenna [48]

Answer:

The number of ways to deal each hand of poker is

1) 10200 possibilities

2) 5108 possibilities

3) 40 possibilities

4) 624 possibilities

5) 123552 possibilities

6) 732160 possibilities

7) 308880 possibilities

8) 267696 possibilities

Step-by-step explanation:

Straigth:

The Straight can start from 10 different positions: from an A, from a 2, 3, 4, 5, 6, 7, 8, 9 or from a 10 (if it starts from a 10, it ends in an A).

Given one starting position, we have 4 posibilities depending on the suit for each number, but we need to substract the 4 possible straights with the same suit. Hence, for each starting position there are 4⁵ - 4 possibilities. This means that we have 10 * (4⁵-4) = 10200 possibilities for a straight.

Flush:

We have 4 suits; each suit has 13 cards, so for each suit we have as many flushes as combinations of 5 cards from their group of 13. This is equivalent to the total number of ways to select 5 elements from a set of 13, in other words, the combinatorial number of 13 with 5 {13 \choose 5} .  However we need to remove any possible for a straight in a flush, thus, for each suit, we need to remove 10 possibilities (the 10 possible starting positions for a straight flush). Multiplying for the 4 suits this gives us

4 * ( {13 \choose 5} -10) = 4* 1277 = 5108

possibilities for a flush.

Straight Flush:

We have 4 suits and 10 possible ways for each suit to start a straight flush. The suit and the starting position determines the straight flush (for example, the straight flush starting in 3 of hearts is 3 of hearts, 4 of hearts, 5 of hearts, 6 of hearts and 7 of hearts. This gives us 4*10 = 40 possibilities for a straight flush.

4 of a kind:

We can identify a 4 of a kind with the number/letter that is 4 times and the remaining card. We have 13 ways to pick the number/letter, and 52-4 = 48 possibilities for the remaining card. That gives us 48*13 = 624 possibilities for a 4 of a kind.

Two distinct matching pairs:

We need to pick the pair of numbers that is repeated, so we are picking 2 numbers from 13 possible, in other words, {13 \choose 2} = 78 possibilities. For each number, we pick 2 suits, we have {4 \choose 2} = 6 possibilities to pick suits for each number. Last, we pick the remaining card, that can be anything but the 8 cards of those numbers. In short, we have 78*6*6*(52-8) = 123552 possibilities.  

Exactly one matching pair:

We choose the number that is matching from 13 possibilities, then we choose the 2 suits those numbers will have, from which we have 4 \choose 2 possibilities. Then we choose the 3 remaining numbers from the 12 that are left ( 12 \choose 3 = 220 ) , and for each of those numbers we pick 1 of the 4 suits available. As a result, we have

13 * 4 * 220 * 4^3 = 732160

possibilities

At least one card from each suit (no mathcing pairs):

Pick the suit that appears twice (we have 4 options, 1 for each suit). We pick 2 numbers for that suit of 13 possible (13 \choose 2 = 78 possibilities ), then we pick 1 number from the 11 remaining for the second suit, 1 number of the 10 remaining for the third suit and 1 number from the 9 remaining for the last suit. That gives us 4*78*11*10*9 = 308880 possibilities.

Three cards of one suit, and 2 of another suit:

We pick the suit that appears 3 times (4 possibilities), the one that appears twice (3 remaining possibilities). Foe the first suit we need 3 numbers from 13, and from the second one 2 numbers from 13 (It doesnt specify about matching here). This gives us

4 * 13 \choose 3 * 3 * 13 \choose 2 = 4*286*3*78 = 267696

possibilities.

7 0
3 years ago
find the probability if two dice are rolled. (enter the value of probability in decimals. round the answer to three decimal plac
spayn [35]

The probability of getting a total of 8 when two dice are rolled is 0.139.

Probability is a number that expresses the likelihood or chance that a specific event will take place. Probabilities can be represented by proportions on a 0–1 scale.

A single die will have six sides with the numbers: 1, 2, 3, 4, 5, and 6. Each of these events is equally likely to occur if the dice are rolled fairly. So the probability of getting any side of the number is 1/6. Therefore, the probability of getting 1 in dice is 1/6, 2 is 1/6, and so on.

Therefore, the total possible outcomes are the multiplication of the total possible outcomes on dice 1 and dice 2, which is 36.

This possible outcome of rolling two dice is given by,

\left\{\begin{array}{ccccccc}(1, 1)&(1, 2)& (1, 3)&(1, 4)&(1, 5)&(1, 6)\\(2, 1)&(2, 2)&(2, 3)&(2, 4)&(2, 5)&(2, 6)\\(3, 1)&(3, 2)&(3, 3)&(3, 4)&(3, 5)&(3, 6)\\(4, 1)&(4, 2)&(4, 3)&(4, 4)&(4, 5)&(4, 6)\\(5, 1)&(5, 2)&(5, 3)&(5, 4)&(5, 5)&(5, 6)\\(6, 1)&(6, 2)&(6, 3)&(6, 4)&(6, 5)&(6, 6)\end{array}\right\}

The probability of getting a total of 8 from both dice is given by, (2, 6) (3, 5) (4, 4) (5, 3) (6, 2). So the number of favorable outcomes is 5 and the total outcome is 36. The probability is P(getting a total of 8 from both dices)=5/36= 0.139.

The answer is 0.139.

The complete question is -

Consider rolling dice and getting a total of 8. Find the probability of two dice are rolled. (Enter the value of probability in decimals. Round the answer to three decimal places).

To know more about dice probability:

brainly.com/question/17239706

#SPJ4

8 0
1 year ago
Help me so confused?
Eva8 [605]

BD is 31 degrees because it is the same.

ADB is 90-31 because it is a right angle ( 59 degrees)

DEC is 180 - (31*2) because the 180 is of the trangle and the 31 is the same on the other side so times 2 then removed from 180

7 0
3 years ago
K/6 + 8 = 5 what does k=?
vesna_86 [32]

Answer:

78

Step-by-step explanation:

(5 + 8) * 6 = k

4 0
2 years ago
Read 2 more answers
Triangle abc is similar to xyz. which proportion can be used to find the unknown side length
Alex17521 [72]

Unknown side length of two similar triangles can be found out by scale factor and any of the side lengths.

Step-by-step explanation:

The similarity is one of the criteria of triangles. Two triangles are similar when their respective sides are in similar ratio or proportion. In layman’s term, it can be understood as a condition in which two triangles have similar shapes but not similar sizes.

If ΔABC is similar toΔ XYZ, then their respective sides would be in proportion to each other.

This means AB/XY=AC/XZ=BC/YZ

This common ratio is often termed as “scale factor”

Hence any sides length can be found out if either of the terms (i.e. scale factor, side ) is given.

7 0
3 years ago
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