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monitta
3 years ago
10

A 1040 kg car and 3360 kg truck undergo a perfectly inelastic collision. before the collision, the car was traveling southward a

t 1.80 m/s and the truck westward at 8.25 m/s. m/s. find the velocity (speed and direction) of the wreckage immediately after the collision.
Physics
1 answer:
alexandr1967 [171]3 years ago
6 0
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What phenomenon causes the fuzzy image? What kind of lens is used to correct this, and how is it corrected?
mamaluj [8]
In optics, chromatic aberration (abbreviated CA; also called chromatic distortion and spherochromatism) is an effect resulting from dispersion in which there is a failure of a lens to focus all colors to the same convergence point.[1] It occurs because lenses have different refractive indices for different wavelengths of light. The refractive index of transparent materials decreases with increasing wavelength in degrees unique to each.
5 0
3 years ago
Read 2 more answers
wheel rotates from rest with constant angular acceleration. Part A If it rotates through 8.00 revolutions in the first 2.50 s, h
Alex73 [517]

Answer:

x2 = 64 revolutions.

it rotate through 64 revolutions in the next 5.00 s

Explanation:

Given;

wheel rotates from rest with constant angular acceleration.

Initial angular speed v = 0

Time t = 2.50

Distance x = 8 rev

Applying equation of motion;

x = vt +0.5at^2 ........1

Since v = 0

x = 0.5at^2

making a the subject of formula;

a = x/0.5t^2 = 2x/t^2

a = angular acceleration

t = time taken

x = angular distance

Substituting the values;

a = 2(8)/2.5^2

a = 2.56 rev/s^2

velocity at t = 2.50

v1 = a×t = 2.56×2.50 = 6.4 rev/s

Through the next 5 second;

t2 = 5 seconds

a2 = 2.56 rev/s^2

v2 = 6.4 rev/s

From equation 1;

x = vt +0.5at^2

Substituting the values;

x2 = 6.4(5) + 0.5×2.56×5^2

x2 = 64 revolutions.

it rotate through 64 revolutions in the next 5.00 s

5 0
3 years ago
What force is needed to give a 4.5-kg bowling ball an acceleration of 9 m/s2?
Sloan [31]
F=ma  
f=4.5*9                                           

40.5 N
hope this help
8 0
3 years ago
Read 2 more answers
If the 20-mm-diameter rod is made of A-36 steel and the stiffness of the spring is k = 55 MN/m , determine the displacement of e
Alinara [238K]

Answer:

σ = 1.09 mm

Explanation:

<u>Step 1:</u> Identify the given parameters

rod diameter = 20 mm

stiffness constant (k) = 55 MN/m = 55X10⁶N/m

applied force (f) = 60 KN = 60 X 10³N

young modulus (E) = 200 Gpa = 200 X 10⁹pa

<u>Step 2:</u> calculate length of the rod, L

K = \frac{A*E}{L}

L = \frac{A*E}{K}

A=\frac{\pi d^{2}}{4}

d = 20-mm = 0.02 m

A=\frac{\pi (0.02)^{2}}{4}

A = 0.0003 m²

L = \frac{A*E}{K}

L = \frac{(0.0003142)*(200X10^9)}{55X10^6}

L = 1.14 m

<u>Step 3:</u> calculate the displacement of the rod, σ

\sigma = \frac{F*L}{A*E}

\sigma = \frac{(60X10^3)*(1.14)}{(0.0003142)*(200X10^9)}

σ = 0.00109 m

σ = 1.09 mm

Therefore, the displacement at the end of A is 1.09 mm

3 0
3 years ago
For a chair to be balanced on one leg, where must the center of gravity be located? A. in the center of the seat B. toward the f
mixer [17]

Answer:

The correct answer is c

Explanation:

When a body is in rotational equilibrium, the relationship must be met

     ∑ τ = 0

     Σ F d = 0

therefore the forces that are exerted on the body that are represented in the center of gravity are different from zero, therefore, to maintain balance the distance must be zero, therefore the center of gravity must be above the leg where the body is balancing

The correct answer is c

6 0
3 years ago
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