Answer:
Uniform Circular Motion
Explanation:
Uniform circular motion can be described as the motion of an object in a circle at a constant speed. As an object moves in a circle, it is constantly changing its direction. At all instances, the object is moving tangent to the circle.
Answer:
Work= -7.68×10⁻¹⁴J
Explanation:
Given data
q₁=q₂=1.6×10⁻¹⁹C
r₁=2.00×10⁻¹⁰m
r₂=3.00×10⁻¹⁵m
To find
Work
Solution
The work done on the charge is equal to difference in potential energy
W=ΔU
![Work=U_{1}-U_{2}\\ Work=-kq_{1}q_{2}[\frac{1}{r_{2}}-\frac{1}{r_{1}} ]\\Work=(-9*10^{9})*(1.6*10^{-19} )^{2}[\frac{1}{3.0*10^{-15} }-\frac{1}{2*10^{-10} } ]\\ Work=-7.68*10^{-14}J](https://tex.z-dn.net/?f=Work%3DU_%7B1%7D-U_%7B2%7D%5C%5C%20Work%3D-kq_%7B1%7Dq_%7B2%7D%5B%5Cfrac%7B1%7D%7Br_%7B2%7D%7D-%5Cfrac%7B1%7D%7Br_%7B1%7D%7D%20%5D%5C%5CWork%3D%28-9%2A10%5E%7B9%7D%29%2A%281.6%2A10%5E%7B-19%7D%20%29%5E%7B2%7D%5B%5Cfrac%7B1%7D%7B3.0%2A10%5E%7B-15%7D%20%7D-%5Cfrac%7B1%7D%7B2%2A10%5E%7B-10%7D%20%7D%20%5D%5C%5C%20%20Work%3D-7.68%2A10%5E%7B-14%7DJ)
Explanation:
a) I = V / R
1.70 = 115 / R
R = 115 / 1.70
R = 67.647
R = 67.65 ohms
Therefore, equivalent resistance is 67.65 ohms
b) Equivalent resistance of circuit from above sum is 67.65 ohms
Given resistance of each bulb is 1.50 ohms
Number bulbs = Equivalent resistance / Resistance of each bulb
= 67.65 / 1.50
= 45
Answer:
1: 19,6 N | 2: 686 N | 3: 705,6 N
Explanation:
Just apply the formula:
1: 2 . 9,8 = 19.6 N
2: (60+10) . 9,8 = 686 N
3: [30 + (6 . 7)] . 9,8
[30 + 42] . 9,8
72 . 9,8 = 705.6 N
Just sum all the weights in the system and then multiply by gravity (9,8 in this case)
Does it give you options?
