Answer:
0.17547 m
Explanation:
m = Mass of block =
v = Velocity of block = 10.8 m/s
k = Spring constant = 125 N/m
A = Amplitude
The kinetic energy of the system is conserved
The amplitude of the resulting simple harmonic motion is 0.17547 m
Which measurement of mass would have the shortest de Broglie wavelength at a given speed? A. 10 kg B. 20 kg C. 30 kg D. 40 kg
1 answer:
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The frequency of a simple harmonic oscillator such as a spring-mass system is given by
where
k is the spring constant
m is the mass attached to the spring.
Re-arranging the formula, we get:
and since we know the constant of the spring:
and the frequency of oscillation:
f=1.00 Hz
we can find the value of the mass attached to it:
where
k is the spring constant
m is the mass attached to the spring.
Re-arranging the formula, we get:
and since we know the constant of the spring:
and the frequency of oscillation:
f=1.00 Hz
we can find the value of the mass attached to it: