Answer:
11 electrons & 11 neutrons
Explanation:
Answer:
0.35 kg
Explanation:
8 cm = 0.08 m
For the block to stay balance, the buoyancy force must be the same as gravity that pulls it down.
Let mass of the block be M, then the gravity would be Mg
Let water density be
, the buoyancy force would be the weight of water that is displaced by the submerged block.
For example, when there is no coin, block is
submerged. The weight of water displaced must be

Which is also the weight of block, of Mg
Therefore M = 31.2A. (1)
As coins are stacked on top of block, h increase, so as weight of water displaced and total weight of block and coins. Now let m be the total weight of coins. The gravity of block and weight must be (M+m)g. And the weight of water displaced is:


Since the linear plot of h vs m has a slope of 0.089 m/kg, we can interpret it as


So from the eq. (1) we can solve for M = 31.2A = 0.35 kg
Heat flux (i) = k.a.temp variation/d
i = 250 J/s or 250w ; d = 2.1 x 10^-3m ; A = 1.9m^2 ; K (Body Fat) = 0.2W/m.Kelvin ; Temp. Var. (Delta T) = ?
-> 250 = 0.2 x 1.9 x deltaT/2.1 x 10^-3
-> 250 x 2.1 x 10^-3 = 0.38 x deltaT
-> 525 x 10^-3 = 38x10^-2 x deltaT
-> deltaT = 525 x 10^-3/ 38 x 10^-2
-> deltaT = 13.81 x 10^(-3 - (-2))
-> deltaT = 13.81 x 10^-1
-> deltaT = 1.381 K
The forces a piano tuner applies to stretch the steel piano wire willl be 1.4 × 10¹¹ N.
<h3>What is force?</h3>
Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration. Its unit is Newton.
The application of a force may be used to describe the steel as an elastic element within a certain range of applied force.
Given data;
Young modulus, E=2.10 × 10¹¹ N/m²
Cross-sectional area,A
Final length,
Initial length,

Hence, the force a piano tuner applies to stretch the steel piano wire willl be 1.4 × 10¹¹ N.
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The mass is moving with an acceleration of 13.299 m/s².
<h3>What is the straight forward meaning of acceleration?</h3>
The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics. They are vector quantities, accelerations.
According to therefore mentioned statement,
the direction of the net force applied on an object determines its acceleration;
according to mentioned data;
F₁=30N
F₂=10N
Net force on object;
F=F₁+F₂
F=F₁y+F₂Cos30°(-x)+F₂ Sinx(-y)
F=3y+10×(√3/2)(-x)+10×(1/2)(-y)
F=ma
ma=-5√3/2(x)+25y
2a=-5√3x/2+25y
a=-5√3x+25y
magnitude(a)=√(-5√3/2)²+(25/2)²
(a) =13.299m/s²
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