Answer:
(D) parasite........................
Answer:
a) Maximum height reached above ground = 2.8 m
b) When he reaches maximum height he is 2 m far from end of the ramp.
Explanation:
a) We have equation of motion v²=u²+2as
Considering vertical motion of skateboarder.
When he reaches maximum height,
u = 6.6sin58 = 5.6 m/s
a = -9.81 m/s²
v = 0 m/s
Substituting
0²=5.6² + 2 x -9.81 x s
s = 1.60 m
Height above ground = 1.2 + 1.6 = 2.8 m
b) We have equation of motion v= u+at
Considering vertical motion of skateboarder.
When he reaches maximum height,
u = 6.6sin58 = 5.6 m/s
a = -9.81 m/s²
v = 0 m/s
Substituting
0= 5.6 - 9.81 x t
t = 0.57s
Now considering horizontal motion of skateboarder.
We have equation of motion s =ut + 0.5 at²
u = 6.6cos58 = 3.50 m/s
a = 0 m/s²
t = 0.57
Substituting
s =3.5 x 0.57 + 0.5 x 0 x 0.57²
s = 2 m
When he reaches maximum height he is 2 m far from end of the ramp.
Each piece will have 1/4 of the mass of the original big cube, but its density will be the same.
Density is a property of a substance, no matter how much or how little of it you have.
A speck of it on the tip of your pinky and a supertankerful of the same substance have the same density.
Answer:
1.63 
Explanation:
The equation 
would be used where:
g = acceleration due to gravity
G = universal gravitational constant (6.67408 × 
)
M = mass
R = radius.
assuming the values following both 10s of the mass and radius are their exponents, which is a little confusing, the values given would simply be substituted.
Anyone can correct me if I'm wrong.
