Question

Unit l2 trigonometry homework 6 law of cosines Does anyone know the answer please help!​

Answer 1

Step-by-step explanation:

The law of cosine states that:

$C^2=B^2+A^2-2AB\cos(\theta)$, where C is the side opposite of angle theta, and A and B are the adjacent sides of the angle.

In this case, A is equal to 21, and B is equal to 30 (or it could also be the other way around). That means that:

$C^2=21^2+30^2-2\cdot21\cdot30\cos(73)\\C=\sqrt{21^2+30^2-2\cdot21\cdot30\cos(73)}=\boxed{31.186722}$ (to nearest 6 digits)

Answer 2

Answer:

102.61

Step-by-step explanation:

assuming that QS is the hypothesis we us the fromula like this:

$30cos(73)$

which gives us 8.7711511417 or we can round to 8.77

assuming that QS is the adjacent  we use:

$\frac{30}{cos(73)}$

which gives us 102.609108595 or rounded to 102.61

looking at both answers we can see that 102.61 would be the correct answer.