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ELEN [110]
3 years ago
5

Unit l2 trigonometry homework 6 law of cosines Does anyone know the answer please help!​

Mathematics
2 answers:
guapka [62]3 years ago
7 0

Step-by-step explanation:

The law of cosine states that:

C^2=B^2+A^2-2AB\cos(\theta), where C is the side opposite of angle theta, and A and B are the adjacent sides of the angle.

In this case, A is equal to 21, and B is equal to 30 (or it could also be the other way around). That means that:

C^2=21^2+30^2-2\cdot21\cdot30\cos(73)\\C=\sqrt{21^2+30^2-2\cdot21\cdot30\cos(73)}=\boxed{31.186722} (to nearest 6 digits)

Sloan [31]3 years ago
3 0

Answer:

102.61

Step-by-step explanation:

assuming that QS is the hypothesis we us the fromula like this:

30cos(73)

which gives us 8.7711511417 or we can round to 8.77

assuming that QS is the adjacent  we use:

\frac{30}{cos(73)}

which gives us 102.609108595 or rounded to 102.61

looking at both answers we can see that 102.61 would be the correct answer.

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Answer:

11). m∠W = 70°

12). m∠M = 95°

13). m∠Q = 135°

14). m∠Q = 55°

15). m∠X = 110°

Step-by-step explanation:

11). m∠W + m∠X = 180° [Consecutive interior angles]

    (24x - 2) + (36x + 2) = 180°

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     Therefore, m∠W = (24x - 2)°

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     Since opposite angles of a parallelogram are equal in measure.

     m∠Y = m∠W = 70°

12). m∠J + m∠K = 180° [Consecutive interior angles]

     (6x + 19) + (8x + 7) = 180°

     14x + 26 = 180

     14x = 180 - 26

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     m∠K = (8x + 7)

     m∠K = 8×11 + 7

     m∠K = 95°

     Since m∠M = m∠K

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13). m∠Q = m∠S [Opposite angles of a parallelogram]

      x + 135 = 2x + 135

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14). m∠Q = m∠S [Opposite angles of a parallelogram]

      14x - 1 = 13x + 3

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      m∠Q = (13x + 3)

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     (19x - 4) = (17x + 8)

      19x - 17x = 12

      2x = 12

      x = 6

      m∠X = (17x + 8)°

      m∠X = 17×6 + 8

      m∠X = 110°

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