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Diano4ka-milaya [45]
3 years ago
9

Are pickles a type of a fruit

Chemistry
1 answer:
zheka24 [161]3 years ago
3 0

Technically, pickles may be considered both a fruit and a vegetable. While they are made from cucumbers, which are a vegetable, the U.S. Supreme Court ruled them a ‘fruit of the vine’ because of their seeds.

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Can some one plz help
blsea [12.9K]

The reaction uses B) 9.0 g Br₂.

 iron + bromine ⟶ product

2.0 g +     <em>x</em> g     ⟶   11.0 g

According to the <em>Law of Conservation of Mass</em>, the total mass of the reactants must equal the total mass of the products.

∴2.0 + <em>x</em> = 11.0

<em>x</em> = 11.0 – 2.0 = 9.0

The reaction uses 9.0 g Br₂.

5 0
3 years ago
In stoichiometric calculations, which quantity MUST be used to convert from one chemical substance to another?
Cloud [144]

The answer is

C) mole ratio

4 0
3 years ago
Which metal will react spontaneously with Cu2+ (aq) at 25°C?
Gwar [14]

Answer:

Mg  

Explanation:

The standard reduction potentials are

                                              <u>E°/V </u>

Au³⁺(aq ) + 3e⁻  ⟶  Au(s);     1.42

Hg²⁺(aq)  + 2e⁻  ⟶  Hg(l);     0.85

Ag⁺(aq)    +   e⁻  ⟶  Ag(s);    0.80

Cu²⁺(aq)   + 2e⁻ ⟶  Cu(s);   0.34

Mg2+(aq) + 2e- ⟶  Mg(s);   -2.38

The more negative the standard reduction potential, the stronger the metal is as a reducing agent.

Mg is the only metal with a standard reduction potential lower than that of Cu, so

Only Mg will react spontaneously with Cu²⁺.

 

5 0
3 years ago
Read 2 more answers
Calculate either [ H 3 O + ] or [ OH − ] for each of the solutions.
STALIN [3.7K]

Answer: Solution A : [H_3O^+]=0.300\times 10^{-7}M

Solution B : [OH^-]=0.107\times 10^{-5}M

Solution C : [OH^-]=0.177\times 10^{-10}M

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration and pOH is calculated by taking negative logarithm of hydroxide ion concentration.

pH=-\log[H_3O^+]

pOH=-log[OH^-}

pH+pOH=14

[H_3O^+][OH^-]=10^{-14}

a. Solution A: [OH^-]=3.33\times 10^{-7}M

[H_3O^+]=\frac{10^{-14}}{3.33\times 10^{-7}}=0.300\times 10^{-7}M

b. Solution B : [H_3O^+]=9.33\times 10^{-9}M

[OH^-]=\frac{10^{-14}}{9.33\times 10^{-9}}=0.107\times 10^{-5}M

c. Solution C : [H_3O^+]=5.65\times 10^{-4}M

[OH^-]=\frac{10^{-14}}{5.65\times 10^{-4}}=0.177\times 10^{-10}M

7 0
3 years ago
Why can more water vapor (water molecules that are in the gas state of matter) be present in warm air than in cold air?
Bond [772]

Answer:

Because warm air is less dense

Explanation:

5 0
3 years ago
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