First, we are given that the inscribed angle of arc CB which is angle D is equal to 65°. This is half of the measure of the arc which is equal to the measure of the central angle, ∠O.
m∠O = 2 (65°) = 130°
Also, the measure of the angles where the tangent lines and the radii meet are equal to 90°. The sum of the measures of the angle of a quadrilateral ACOB is equal to 360°.
m∠O + m∠C + m∠B + m∠A = 360°
Substituting the known values,
130° + 90° + 90° + m∠A = 360°
The value of m∠A is equal to 50°.
<em>Answer: 50°</em>
25 miles and 5 miles because you only multiply two sides to find the area 25•5=125
6/10 is equal to 0.60
9/12 is equal to 0.75
your answer is not above for D but if D is < then that would be the correct answer :)
Answer:
-15x+5
Step-by-step explanation:
Multiply you'll get your solution
Answer:
Step-by-step explanation:
