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2 years ago

9

Bruh i can't and I need help

1 answer:

polet [3.4K]2 years ago

8 0

I think the answer is d if it followed the sequence or should be -1 but that’s not an option so my best guess is d hope this helps

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Suppose a random variable x is best described by a uniform probability distribution with range 22 to 55. Find the value of a tha

const2013 [10]

Answer:

(a) The value of <em>a</em> is 53.35.

(b) The value of <em>a</em> is 38.17.

(c) The value of <em>a</em> is 26.95.

(d) The value of <em>a</em> is 25.63.

(e) The value of <em>a</em> is 12.06.

Step-by-step explanation:

The probability density function of <em>X</em> is:

$f_{X}(x)=\frac{1}{55-22}=\frac{1}{33}$

Here, 22 < X < 55.

(a)

Compute the value of <em>a</em> as follows:

$P(X\leq a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.95\times 33=[x]^{a}_{22}\\\\31.35=a-22\\\\a=31.35+22\\\\a=53.35$

Thus, the value of <em>a</em> is 53.35.

(b)

Compute the value of <em>a</em> as follows:

$P(X< a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.49\times 33=[x]^{a}_{22}\\\\16.17=a-22\\\\a=16.17+22\\\\a=38.17$

Thus, the value of <em>a</em> is 38.17.

(c)

Compute the value of <em>a</em> as follows:

$P(X\geq a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.85=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.85\times 33=[x]^{55}_{a}\\\\28.05=55-a\\\\a=55-28.05\\\\a=26.95$

Thus, the value of <em>a</em> is 26.95.

(d)

Compute the value of <em>a</em> as follows:

$P(X\geq a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.89=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.89\times 33=[x]^{55}_{a}\\\\29.37=55-a\\\\a=55-29.37\\\\a=25.63$

Thus, the value of <em>a</em> is 25.63.

(e)

Compute the value of <em>a</em> as follows:

$P(1.83\leq X\leq a)=\int\limits^{a}_{1.83} {\frac{1}{33}} \, dx \\\\0.31=\frac{1}{33}\cdot \int\limits^{a}_{1.83} {1} \, dx \\\\0.31\times 33=[x]^{a}_{1.83}\\\\10.23=a-1.83\\\\a=10.23+1.83\\\\a=12.06$

Thus, the value of <em>a</em> is 12.06.

7 0

3 years ago

Susan has 50% more books than Michael. Michael has 40 books. If Michael buys 8 more books, will Susan have more or less books th

ololo11 [35]

Answer:

Susan has more books than Michael.

Step-by-step explanation:

If Susan has 50% more books and Michael has 40 books, that means Susan has 1.5 times 40 = 60

40 + 8 = 48

60 is more than 48, so Susan has more books than Michael

7 0

2 years ago

An electric sale gives a reading equal to the true weight plus a random error that isnormally distributed with mean 0 and standa

Pepsi [2]

Answer:

a) 95% confidence interval estimate of the true weight is (3.026, 3.274)

b) 99% confidence interval estimate of the true weight is (2.944, 3.356)

Step-by-step explanation:

Confidence Interval can be calculated using M±ME where

M is the mean of five successive weightings (3.150)

ME is the margin of error from the mean

And margin of error (ME) can be calculated using the formula

ME= $\frac{t*s}{\sqrt{N} }$ where

t is the corresponding statistic in the given confidence level and degrees of freedom(t-score)

s is the standard deviation of the random error (0.1)

N is the sample size (5)

Using the numbers 95% confidence interval estimate of the true weight is:

3.150± $\frac{2.776*0.1}{\sqrt{5} }$ ≈3.150±0.124

And 99% confidence interval estimate of the true weight is:

3.150± $\frac{4.604*0.1}{\sqrt{5} }$ ≈3.150±0.206

3 0

3 years ago

What is the solution of n/6 = 36

igor_vitrenko [27]

Answer:

n=216.

Step-by-step explanation:

Very simple problem - we just have to multiply both sides by 6, which will get rid of the 6 on the left.

36 x 6 = 216

8 0

2 years ago

PLS HELP FOR BRAINLIST...

Ahat [919]

Answer is C ig I’m sowwy if I’m wrong

8 0

2 years ago