Answer:
6x ( 3x +4)
X =0 and x = 4/3 or x = 1 1/3
Step-by-step explanation:
Take the common factors out,
Here x is common to both equation and also 6 is common to both equation
So,
6x ( 3x + 4) = 0
So it can be solved by
X = 0 and x = 4/3
Answer:
The solutions are a₁ = -4/19 i, a₂ = 4/19 i and a₃ = -1/4
Step-by-step explanation:
Given the equation 76a³+19a²+16a=-4, for us to solve the equation, we need to find all the factors of the polynomial function. Since the highest degree of the polynomial is 3, the polynomial will have 3 roots.
The equation can also be written as (76a³+19a²)+(16a+4) = 0
On factorizing out the common terms from each parenthesis, we will have;
19a²(4a+1)+4(4a+1) = 0
(19a²+4)(4a+1) = 0
19a²+4 = 0 and 4a+1 = 0
From the first equation;
19a²+4 = 0
19a² = -4
a² = -4/19
a = ±√-4/19
a₁ = -4/19 i, a₂ = 4/19 i (√-1 = i)
From the second equation 4a+1 = 0
4a = -1
a₃ = -1/4
B. 36
because if you find the area of the big square its 5×6 and the smaller rectangle is 3×2
so its 30+6
36
Answer:
Part 1) 
Part 2) 
Part 3) 
Part 4) 
Step-by-step explanation:
step 1
Find the value of x
In the large right triangle
----> by CAH (adjacent side divided by the hypotenuse)
Remember that

substitute

solve for x
---> improper fraction
step 2
Find the value of z
In the large right triangle
Applying the Pythagorean Theorem

substitute the value of x

solve for z




simplify

step 3
Find the value of y
In the right triangle of the right
---> by SOH (opposite side divided by the hypotenuse)
substitute the given values of y and z
Remember that

so

solve for y


step 4
Find the value of b
In the right triangle of the right
---> by CAH (adjacent side divided by the hypotenuse)
substitute the given values of y and z
Remember that

so

solve for y

