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2 years ago

Simplify: ((x-5)3/2)^2/3 X-5 (x - 5)^2 (x – 5^)3

Mathematics

1 answer:

netineya [11]2 years ago

7 0

Answer:

x - 5

Step-by-step explanation:

$((x - 5) {}^{ \frac{3}{2} } ) {}^{ \frac{2}{3} }$

$(x - 5) {}^{ \frac{3}{2} } { \times }^{ \frac{2}{3} }$

$(x - 5) {}^{ \frac{6}{6} }$

$(x - 5) {}^{1}$

Therefore x - 5

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Find the value of X° a.25° b.85° c.75° d.105°

sdas [7]

The answer is C. 75. Hope this helps.

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3 years ago

A sector with an area of \goldE{48\pi,\text{cm}^2}48πcm 2 start color #a75a05, 48, pi, start text, c, m, end text, squared, end

erik [133]

Answer:

3/8 π radians

Step-by-step explanation:

The Area of a sector when then central angle is in radians = 1/2r² θ

Where

θ = central angle = ?

r = 16 cm

Area of the sector = 48πcm²

Hence

Central angle = Area of a sector ÷ (1/2r²)

= 48πcm² ÷ (1/2 × 16²)

= 48πcm² ÷ 128

Central angle = 3/8π radians

Therefore, Central angle = 3/8π radians

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2 years ago

2x + 2y = -2 3x - 2y = 12 Solve By Elimination Pls give me the hole equation

Sholpan [36]

Answer:

x = 2

y = -3

Step-by-step explanation:

2x + 2y = -2, then 2y = -2 - 2x

3x - 2y = 12, then 2y = 3x - 12

so:

-2 - 2x = 3x - 12

add 2x and 12 to each side of the equation:

5x = 10

divide both sides by 5:

x = 2

2y = 3(2) - 12

2y = -6

divide both sides by 2:

y = -3

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2 years ago

HELP PLZZZZ!!!!!!!!!!!!!!

Sergio039 [100]

Answer:

Step-by-step explanation:

6 0

2 years ago

A ladder 16 feet long is leaning against the wall of a tall building. The base of the ladder is moving away from the wall at a r

svet-max [94.6K]

Answer:

a. 0.588

b. 0.0722

c. 4.576 sqft/sec

Step-by-step explanation:

Let b and h denote the base and height as indicated in the diagram. By pythagoras theorem, $h^2 + b^2 = 16^2 = 256 \dotsc\;(1)$ because it is a right angle triangle.

It is given that $\frac{db}{dt} = 1$

Now differentiate (1) with respect to t (time) :

$\displaystyle{2h\frac{dh}{dt} + 2b\frac{db}{dt} = 0 \implies \frac{dh}{dt} = -\frac{b}{h} \frac{db}{dt}}$

$\displaystyle{=-\frac{b}{\sqrt{256 - b^2}} \frac{db}{dt} = -\frac{8}{13.856} \times 1 = -0.588}$

The minus sign indicates that the value of h is actually decreasing. The required answer is 0.588.

b. From the diagram, infer that $16 \sin{\theta} = b$ . When b = 8, then $\theta = \arcsin{0.5} = \ang{30}$ .

Differentiate the above equation w.r.t t

$\displaystyle{16 \cos{\theta} \frac{d\theta}{dt} = \frac{db}{dt} \implies \frac{d\theta}{dt} = \frac{1}{16 \cos{\theta}} = \frac{1}{13.856} = \mathbf{0.0722}}$

c. The area of the triangle is given by $A = 0.5\times h \times b$ . Differentiating w.r.t t,

$\displatstyle{\frac{dA}{dt} = 0.5 b \frac{dh}{dt} + 0.5 h \frac{db}{dt}}$

Plugging in b = 8, h = 13.856, $\frac{dh}{dt} = -0.588$ ,

$\frac{dA}{dt} = -2.352 + 6.928 = \mathbf{4.576 ft^2/sec}$

8 0

3 years ago