1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
balu736 [363]
2 years ago
10

Consider four different samples: aqueous LiBr, molten LiBr, aqueous LiF, and molten LiF. Current run through each sample produce

s one of the following products at the anode: liquid bromine, fluorine gas, or oxygen gas. Match each sample to its anodic product from aqueous LiBr, Molten LiBr, aqueous LiF, and molten LiFA. Liquid bromine,
B. Fluorine gas,
C. oxygen gas
Chemistry
1 answer:
Verizon [17]2 years ago
5 0

Answer:

Following are the solution to the given question:

Explanation:

Please find the matching in attached file.

During the electrolysis of Molten LiBr : Li is reduced and Br are oxidized .

Lithium Metal is produced at the Cathod during the electrolysis of Molten LiBR .

In the aquous LiBr : In aquous LiBr potential of Li is greater than the of water then Li is reduced to produce solid Li ion.  As well As aqueous LiF ( electrolysis)and Molten LiF electrolysis produce the gas.  

aqueous LiF: Oxygen gas.

Molten LiF : Flourine gas.  

You might be interested in
A 1.11 g sample of caffeine, C8H10N4O2, burns in a constant-volume calorimeter that has a heat capacity of 7.85 kJ/K. The temper
VladimirAG [237]

Answer:

401135 kJ

Explanation:

From the balanced quation,

(q/n) = CΔE

Molar heat of combustion = 7.85kJk × (303.81-298.70)k

                                            = 7.85kj × 5.11

                                             = 40.1135kj

4 0
3 years ago
Why is peer review important when publishing experimental results? A. Peer review makes the experiment repeatable. B. Peer revie
MA_775_DIABLO [31]
The answer is D. At least that's what I think.
4 0
3 years ago
Read 2 more answers
How many atoms are there in 1 g of argon?
amm1812

Answer:

1.5057×10^22 atom

Explanation:

As we

1 mole of argon = 40 g of argon

i.e 40 g of argon = 1 mole of argon

1 g of argon = 1/40 mole of argon

1 mole of argon = 6.023×10^23 atom of argon

1/40 mole if argon = 1/40 ×6.023×10^23

= 1.5057×10^22

7 0
2 years ago
What type of compound is fe3n2
Shkiper50 [21]

Fe3N2, also known as Iron (II) nitride, is an ionic compound.


Ionic compounds are compounds that consists of metals and non-metals bonded with ionic bonds. The metal ion gives up electron(s) to the non-metals.


Since iron is a metal and nitrogen is an non-metal, the bond they would form would be an ionic bond. Iron gives up 2 electrons to form iron(II) ion, while nitrogen gains 3 electrons to form nitride ion. Since one iron cannot let a nitrogen gain 3 electrons, so in the compound, there would be 3 iron (ii) ions that has given up 6 electrons in total while 2 nitride ions have gained 6 electrons in total.

8 0
3 years ago
An equilibrium mixture of PCl5(g), PCl3(g), and Cl2(g) has partial pressures of 217.0 Torr, 13.2 Torr, and 13.2 Torr, respective
katovenus [111]

Answer:

The new partial pressures after equilibrium is reestablished:

PCl_3,p_1'=6.798 Torr

Cl_2,p_2'=26.398 Torr

PCl_5,p_3'=223.402 Torr

Explanation:

PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)

At equilibrium before adding chlorine gas:

Partial pressure of the PCl_3=p_1=13.2 Torr

Partial pressure of the Cl_2=p_2=13.2 Torr

Partial pressure of the PCl_5=p_3=217.0 Torr

The expression of an equilibrium constant is given by :

K_p=\frac{p_1}{p_1\times p_2}

=\frac{217.0 Torr}{13.2 Torr\times 13.2 Torr}=1.245

At equilibrium after adding chlorine gas:

Partial pressure of the PCl_3=p_1'=13.2 Torr

Partial pressure of the Cl_2=p_2'=?

Partial pressure of the PCl_5=p_3'=217.0 Torr

Total pressure of the system = P = 263.0 Torr

P=p_1'+p_2'+p_3'

263.0Torr=13.2 Torr+p_2'+217.0 Torr

p_2'=32.8 Torr

PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)

At initail

(13.2) Torr     (32.8) Torr                        (13.2) Torr

At equilbriumm

(13.2-x) Torr     (32.8-x) Torr                        (217.0+x) Torr

K_p=\frac{p_3'}{p_1'\times p_2'}

1.245=\frac{(217.0+x)}{(13.2-x)(32.8-x)}

Solving for x;

x = 6.402 Torr

The new partial pressures after equilibrium is reestablished:

p_1'=(13.2-x) Torr=(13.2-6.402) Torr=6.798 Torr

p_2'=(32.8-x) Torr=(32.8-6.402) Torr=26.398 Torr

p_3'=(217.0+x) Torr=(217+6.402) Torr=223.402 Torr

6 0
3 years ago
Other questions:
  • The taste of acid is sour​
    6·2 answers
  • WILL GIVE BRAINLY
    7·1 answer
  • What is the maximum mass of s8 that can be produced by combining 89.0 g of each reactant?
    11·1 answer
  • The partial pressure of argon in the atmosphere is 0.00934 atm. Calculate the partial pressure in mmHg andtorr . Round each of y
    5·1 answer
  • Dose anyone know what I would do to complete this thanks:)??
    12·1 answer
  • Is Pb --> PbSO4 reduction half reaction?​
    6·1 answer
  • If you have 5.22*1022 molecules of glucose (C6H12O6) how many grams is this?
    12·1 answer
  • Astronomers observed that the orbit of Uranus was not uniform. Therefore, they hypothesized the existence of another planet. Thi
    7·1 answer
  • Describe the properties of noble gases. Based on their electronic arrangement, explain whether they can exist alone in nature.
    14·1 answer
  • A gas cylinder contains exactly 1 mole of oxygen gas (O2). How many molecules of oxygen are in the cylinder?.
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!