Answer:
2NaCl + H2SO4 ----> Na2SO4 + 2HCl
Explanation:
The correct electronic configuration of vanadium 23 is
1s^22s^22p^63s^23p^64s^23d^3
This electronic configuration is correct because it obeys the Aufbau principle which state that electrons fill the atomic orbital of the lowest energy before occupying the higher level. S orbital can occupy a total of 2 electrons, p orbital can occupy a total of 6 electrons while d orbital can occupy a total of 10 electrons. in the electronic configuration above an s orbital is filled before p orbital while the p orbital is filled before the d orbital .
O3 + M2+(aq) + H2O(l) => O2(g) + MO2(s) + 2 H+
Eo(cell) = Eo(O3/O2) - Eo(MO2/M2+)
0.44 = 2.07 - Eo(MO2/M2+)
Eo(MO2/M2+) = 1.59 V
Yes. It does contain Ions.