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Dmitriy789 [7]
3 years ago
9

A 20 ft tall ladder standing next to a statue casts a 12 ft shadow. If the statue casts a shadow that is 9 ft long then how tall

is it?
Mathematics
1 answer:
Greeley [361]3 years ago
8 0

Given that,

Length of the ladder = 20 ft

It casts a 12 ft shadow

To find,

If the statue casts a shadow that is 9 ft long then how tall is it?

Solution,

Let the ladder be x ft tall.

20 ft tall ladder = 12 ft shadow

9 ft tall ladder =

\dfrac{20}{12}\times 9\\\\=15\ ft

Hence, the required length is 15 ft.

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german

Answer:

D

Step-by-step explanation:

4x - 2(x + 3) = 8

Use distributive property

4x -2x - 6 = 8

2x - 6 = 8

2x = 8 + 6

2x = 14

x = 14 ÷ 2

x = 7

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4 years ago
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(2,3)

Step-by-step explanation:

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3 years ago
What is the value of the expression 6+18 % 3x4
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4 years ago
HELP PRETTY PLEASE THIS IS URGENT NEED IN THE NEXT HOUR!!
zmey [24]

Answer:

(- 2, 6 )

Step-by-step explanation:

Given the equations

3x + 2y = 6 → (1)

\frac{2}{3} y - x = 6 ( multiply through by 3 to clear the fraction )

2y - 3x = 18 ( add 3x to both sides )

2y = 18 + 3x → (2)

Substitute 2y = 18 + 3x into (1)

3x + 18 + 3x = 6

6x + 18 = 6 ( subtract 18 from both sides )

6x = - 12 ( divide both sides by 6 )

x = - 2

Substitute x = - 2 into (1) and solve for y

3(- 2) + 2y = 6

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7 0
3 years ago
The rectangle below has an area of x2 + 11x + 28 square meters and a length of 2 + 7 meters.
Troyanec [42]
<h3><u>Question:</u></h3>

The rectangle below has an Área of x^2 + 11x + 28 square meters and a length of x+7 meters. What expression represents the width of the rectangle?

<h3><u>Answer:</u></h3>

The expression representing width of rectangle is (x + 4) meters

<h3><u>Solution:</u></h3>

Given that rectangle has an area x^2 + 11x + 28 square meters and a length of x + 7 meters

To find: width of the rectangle

<em><u>The area of rectangle is given as:</u></em>

\text {Area of rectangle }=\text { length } \times \text { width }

Here area = x^2 + 11x + 28 square meters

length = x + 7 meters

<em><u>Substituting the values in given formula,</u></em>

\begin{array}{l}{\text { width }=\frac{x^{2}+11 x+28}{x+7}} \\\\ {\text { width }=\frac{x^{2}+4 x+7 x+28}{x+7}} \\\\ {\text { width }=\frac{x(x+4)+7(x+4)}{x+7}} \\\\ {\text { width }=\frac{(x+4)(x+7)}{x+7}}\end{array}

Cancelling (x + 7) on numerator and denominator,

\text { width }=(x+4)

Thus expression representing width of rectangle is (x + 4) meters

3 0
3 years ago
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