What is the equation of the exponential curve that passes through the points (0,3) and (5,96)?

Please I don’t understand help me?!

prohojiy [21]

Answer:

BD = 35

Step-by-step explanation:

Calculate CD in right triangle ABC, then BD in right triangle BCD

Using Pythagoras' identity in both triangles.

The square on the hypotenuse is equal to the sum of the squares on the other two sides.

In Δ ADC

CD² + AD² = AC² , substitute values

CD² + 9² = 15²

CD² + 81 = 225 ( subtract 81 from both sides )

CD = 144 ( take the square root of both sides )

CD = $\sqrt{144}$ = 12

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In Δ BCD

BD² + CD² = BC² , substitute values

BD² + 12² = 37²

BD² + 144 = 1369 ( subtract 144 from both sides )

BD² = 1225 ( take the square root of both sides )

BD = $\sqrt{1225}$ = 35

5 0

3 years ago

Read 2 more answers

What is the slope of the line that contains the points (4, –1) and (–1, 4)?

BaLLatris [955]

I believe the correct answer is B. -5

4 0

3 years ago

Read 2 more answers

A wildlife audit was recently conducted in Port Augusta, the results of which were as follows: Amphibians Insects Fish Reptiles

r-ruslan [8.4K]

Answer:

The relative frequency of mammals in the survey is 30%.

Step-by-step explanation:

Relative frequency is the ratio of the occurrence of a singular event and the total number of outcome

Amphibians Insects Fish Reptiles Birds Mammals

12 30 9 25 22 42

Relative frequency = $= \frac{\text{ (number of trials that are successful)}}{\text{(total number of trials)}}$

Total number of wildlife animals = 12+ 30 +9 +25+22+42 = 140

Now the relative frequency of mammals in the survey = $\frac{\text{total number of mammals}}{\text{ Total number of animals}}$

the relative frequency of mammals in the survey = $\frac{42}{140}$ = 0.3

Converting into percentage , we get

= $0.3 \times 100$

= 30 %

5 0

3 years ago

Please can someone do this for me? thanks alot x

Nimfa-mama [501]

Answer:

Learning Objective: Use the mean and range to compare the spread and averages.

a) Sarah Mean = 70.9, Katie Mean = 78.9

b) Sarah Range = 15, Katie Range = 25

c) Sentences

- The mean shows, on average, Sarah was 8 seconds quicker than Katie.

- The range shows that Sarah was more consistent with her times. Katie had a larger spread of times which shows she was less consistent.

Step-by-step explanation:

Given:

Sarah's Data Set:

79, 70, 68, 75, 69, 64, 69, 75, 64, 76

Katie's Data Set:

79, 79, 76, 81, 89, 76, 64, 85, 82, 78

To Find:

The mean and range of both data sets separately.

Work:

The mean of a data set is commonly known as the average. You find the mean by taking the sum of all the data values and dividing that sum by the total number of data values. The formula for the mean of a population is $\mu = \frac{{\sum}x}{N}$ .

The formula for the mean of a sample is $\bar{x} = \frac{{\sum}x}{n}$ .

Both of these formulas use the same mathematical process: find the sum of the data values and divide by the total. For the data values given above, the solution is: $\frac{709}{10} = 70.9$