3. Find the area of a rhombus If the length of one diagonal is 12 inches and the length of the other is 18 inches.

Mathematics

1 answer:

Nata [24]3 years ago

5 0

I think it’s 16 I could be wrong but I worked it out how I know to and hopefully it’s right for you!

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Transform the standard form equation into slope intercept form:15=10x-5y

arsen [322]

Answer:

10x - 5y = 15

-5y = -10x + 15

y = 2x - 3

Step-by-step explanation:

7 0

3 years ago

The table shows numbers with the ratio x : y? Find the missing number?

prisoha [69]

X| 1 | 15 | 225 |
y| 4 | ? | 900 |

$\dfrac{y}{x}=const.$

therefore

[tex]\dfrac{4}{1}=4;\ \dfrac{900}{225}=4;\ \dfrac{?}{15}=4\to?=60[\tex]

Answer: ? = 60

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3 years ago

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1. Let f(x, y) be a differentiable function in the variables x and y. Let r and θ the polar coordinates,and set g(r, θ) = f(r co

Olenka [21]

Answer:

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}\\$

Step-by-step explanation:

First, notice that:

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}cos(\frac{\pi}{4}),\sqrt{2}sin(\frac{\pi}{4}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}(\frac{1}{\sqrt{2}}),\sqrt{2}(\frac{1}{\sqrt{2}}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(1,1)\\$

We proceed to use the chain rule to find $g_{r}(\sqrt{2},\frac{\pi}{4})$ using the fact that $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ to find their derivatives:

$g_{r}(r,\theta)=f_{r}(rcos(\theta),rsin(\theta))=f_{x}( rcos(\theta),rsin(\theta))\frac{\delta x}{\delta r}(r,\theta)+f_{y}(rcos(\theta),rsin(\theta))\frac{\delta y}{\delta r}(r,\theta)\\$