0.1875 mol of Na2CO3 needed to react with the 750 mL of 0.250 M H2SO4.
The given reaction between Na2CO3 and H2SO4 are already balanced.
Na2CO3 + H2SO4 → Na2SO4 + CO2.H2O
First, let us determine the number of moles of H2SO4.
Molarity (mol/L) = number of moles of H2SO4 / volume of H2SO4
0.250 M = number of moles of H2SO4 / [(750 mL)(1 L/1000 mL)]
number of moles of H2SO4 = 0.1875 mol
Then, let us determine the number of moles of Na2CO3 that would react with 0.1875 mol H2SO4.
number of moles of Na2CO3 = moles of H2SO4 * stoichiometric ratio
number of moles of Na2CO3 = 0.1875 mol H2SO4 * (1 mol Na2CO3/ mol H2SO4)
number of moles of Na2CO3 = 0.1875 mol Na2CO3
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6.21 x 10^3 = (Move decimal point 3 spaces to the right)
6210
6210 (0.1050)
652.05
The higher the slope of a ramp the more velocity and speed the marvel will gain, which means more distance traveled
Going from left to right, they are ordered by increase in atomic number
Answer:
Kindly check the explanation section.
Explanation:
When the Arsenic acid,H3AsO4 is put in water it dissociates to form or give out 1 proton, 2 protons or 3 protons that is 1H^+, 2H^+ and 3H^+. Check the equation showing the dissociation reactions as given below;
H3AsO4 ===========> H^+ + AsO4^-
H3AsO4 ===========> 2H^+ + AsO4^2-
H3AsO4 ===========> 3H^+ + AsO4^3-
Therefore, the total charge balance is given as:
[H^+] =[OH^-] + [ AsO4^-] + 2[ AsO4^2-] + 3[ AsO4^3-].
Kindly note that the [OH^-] is from water.
