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Vilka [71]
3 years ago
12

What is the IMA of the 1 st class lever in the graphic given? 2 3 0.5

Chemistry
2 answers:
Rainbow [258]3 years ago
7 0

Answer:

IMA = 2

Explanation:

IMA= din/dout

IMA= 3/1.5

IMA= 2

Zina [86]3 years ago
6 0

Answer:

I believe the answer isT 2.

Explanation:

he formula for IMA of a first-class lever is effort-distance/resistance-distance.

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Answer:

d) atmosphere pressure

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A Calorie unit used in food is equal to the amount of energy necessary to raise the temperature of 1 kilogram of water ________
Kitty [74]

A Calorie unit used in food is equal to the amount of energy necessary to raise the temperature of 1 kilogram of water by <u>1</u> degrees Celsius.

<h3>What is One Calorie ?</h3>

The amount of heat energy required to raise the temperature by 1 gram of water through 1°C is known as One Calorie.

1 Calorie = 4.18 J

Thus from the above conclusion we can say that A Calorie unit used in food is equal to the amount of energy necessary to raise the temperature of 1 kilogram of water by <u>1</u> degrees Celsius.

Learn more about the One calorie here: brainly.com/question/1061571

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2 years ago
Sand dunes are created when the wind carrying the sand runs into an obstacle A. True B. False
Troyanec [42]

A. True

They are formed behind an obstacle when the wind blows the sand up to it.

3 0
3 years ago
Maria is baking cookies. She mixes water, flour, sugar, baking powder, butter and chocolate chips and then measures the mass of
Mrrafil [7]

Answer:

The law of conservation of mass was obeyed since some of the mass evaporated while the cookies were baking.

Explanation:

Maria mixes water, flour, sugar, baking powder, butter and chocolate chips and then measures the mass of her ingredients.

Initial mass of ingredients = 1053 g

Final mass = 845 g

All these information are not of any great help.

Law of conservation of mass states that:

For any system closed to all transfers of matter and energy, the mass of the system can not change with respect to time, as system's mass cannot change, any mass can neither be added nor be removed.

In this process of baking, considering the cookies as our system, they never formed a closed system. Hence were free for evaporation.

During the process of baking, water from dough must have evaporated and mass must have reduced.

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3 years ago
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Empirical formula of a compound composed of 32.1 g potassium (k) and 6.57 g oxygen (o)?
tester [92]

The empirical formula is K₂O.

The empirical formula is the <em>simplest whole-number ratio</em> of atoms in a compound.

The <em>ratio of atom</em>s is the same as the <em>ratio of moles</em>.

So, our job is to calculate the <em>molar ratio</em> of K to O.

Step 1. Calculate the <em>moles of each element </em>

Moles of K = 32.1 g K × (1 mol K/(39.10 g K =) = 0.8210 mol K

Moles of O = 6.57 g O × (1 mol O/16.00 g O) = 0.4106 mol 0

Step 2. Calculate the <em>molar ratio of each elemen</em>t

Divide each number by the smallest number of moles and round off to an integer

K:O = 0.8210:0.4106 = 1.999:1 ≈ 2:1

Step 3: Write the <em>empirical formula </em>

EF = K₂O

5 0
3 years ago
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