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yulyashka [42]
3 years ago
13

Please solve the question with the process​

Mathematics
1 answer:
loris [4]3 years ago
8 0

Answer:

Step-by-step explanation:

1-2(2x+1)=1-(x-1)

-1(2x+1)=1-(x-1)

-2x-1=1-x-1

-2x+x=0+1

-x=1

x=-1

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I think it’s 0.85d, but i’m not sure
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I’m not sure how to slove this problem it’s a equilateral triangle and I’m trying to find out what the side is equal to.
Lerok [7]

Answer:

AB = 5/4 y - 1  = 5/4 (12/13) -1 = 2/13

AC= 7/3 y - 2 = 7/3 (12/13) -2 = 2/13

Step-by-step explanation:

Because it is a equilateral triangle, it means all sides have the same length.

AB = AC

5/4 y - 1 = 7/3 y - 2

5/4 y - 7/3 y = -2 +1

-13/12 y = -1

y = 12/13

input y to the equation.

AB = 5/4 y - 1  = 5/4 (12/13) -1 = 2/13

AC= 7/3 y - 2 = 7/3 (12/13) -2 = 2/13

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6 0
3 years ago
What does simplify the expression mean in algebra?
Pavel [41]
Reduce the number of terms in the expression by operating on like terms 
for example
Simplify
x^2 - 3x + 4 + x^2 + 6x - 6

the like terms are the x^2 and x^2 , -3x and 6x and  4 and -6 

so we have
x^2 + x^2 - 3x + 6x + 4 - 6
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5 0
3 years ago
Read 2 more answers
Find the point on the graph of the given function at which the slope of the tangent line is the given slope.
mezya [45]

Answer:

A ( -2 , 9 )

Step-by-step explanation:

<u>Idea:</u> You find the first derivative of f(x), and then set it equal to the desired slope. You'll find some x. That we will use to find the point.

f'(x) = 3x^2 + 12x + 20

f'(x) = 8

3x^2 + 12x + 20 = 8

3x^2 + 12x + 12 = 0

3 ( x^2 + 4x + 4 ) = 0

3 ( x + 2 )^2 = 0

x + 2 = 0

x = -2

So, the desired point is:

A ( -2, f(-2) ) --> A ( -2 , 9 )

3 0
3 years ago
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