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yulyashka [42]
3 years ago
13

Please solve the question with the process​

Mathematics
1 answer:
loris [4]3 years ago
8 0

Answer:

Step-by-step explanation:

1-2(2x+1)=1-(x-1)

-1(2x+1)=1-(x-1)

-2x-1=1-x-1

-2x+x=0+1

-x=1

x=-1

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Answer:

(1)csc A=\dfrac{17}{8}

(2)sec A=\dfrac{17}{15}

Step-by-step explanation:

<u />Tan A=\dfrac{8}{15}\\$In Trigonometry, $Tan A=\dfrac{Opposite}{Adjacent}\\$Therefore:\\Opposite=8, Adjacent=15<u />

Using Pythagoras theorem

Hypotenuse^2=Opposite^2+Adjacent^2\\Hypotenuse^2=8^2+15^2\\Hypotenuse^2=289\\Hypotenuse^2=17^2\\Hypotenuse=17

<u>Question 1</u>

Now, cosecant = 1/sin

Therefore:

csc A=\dfrac{Hypotenuse}{Opposite}\\csc A=\dfrac{17}{8}

<u>Question 2</u>

Now, secant = 1/cos

Therefore:

sec A=\dfrac{Hypotenuse}{Adjacent}\\sec A=\dfrac{17}{15}

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