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kicyunya [14]
2 years ago
7

PLEASE HELPP!!!

Mathematics
1 answer:
gogolik [260]2 years ago
4 0

Answer:

Area of triangle B is 112 cm²

Option A is correct option.

Step-by-step explanation:

The dimensions of triangle B are twice the dimensions of triangle A.

Area of triangle A = 28 cm²

We need to find area of triangle B

We know that if base = b and height = h for triangle A

The area of triangle A will be: Area_A=\frac{1}{2}\times b \times h

The dimensions for triangle B will be:

h_B = 2 h_A\\b_B = 2 b_A

Putting in formula we get:

Area_B=\frac{1}{2}\times b\times h \\Area_B=\frac{1}{2}\times (2b)\times 2(h)\\Area_B=4( \frac{1}{2}\times b\times h)\\Area_B=4(Area_A)

SO, we get Area_B=4(Area_A)\\

We have Area_A = 28 cm²

Area of triangle B Area _B is:

Area_B=4(28)\\Area_B=112\:cm^2

So, Area of triangle B is 112 cm²

Option A is correct option.

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Mademuasel [1]
The correct answer is:  [B]:  "40 yd² " .
_____________________________________________________
First, find the area of the triangle:

The formula of the area of a triangle, "A":

A = (1/2) * b * h ; 

in which:  " A = area (in units 'squared') ;  in our case, " yd² " ; 

                 " b = base length" = 6 yd.  

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→  A = (1/2) * b * h = (1/2) * (6 yd) * (8 yd) = (1/2) * (6) * (8) * (yd²) ; 
                                                                 
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___________________________________________________
Now, find the area, "A", of the square:

The formula for the area, "A" of a square:

   A = s² ;

in which:  "A = area (in "units squared") ; in our case, " yd² " ;
                 
                 "s = side length (since a 'square' has all FOUR (4) equal side lengths);

 A = s²  = (4 yd)² = 4² * yd² =  "16 yd² "
_________________________________________________
Now, we add the areas of BOTH the triangle AND the square:
_________________________________________________
        →  " 24 yd²  +  16 yd² " ; 

to get:  " 40 yd² " ;  which is:  Answer choice:  [B]:  " 40 yd² " .
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