The magnitude of velocity for this car is equal to 1.5 m/s.
<u>Given the following data:</u>
- Momentum of car = 3,000 kgm/s.
To calculate the magnitude of velocity for this car:
<h3>What is momentum?</h3>
In Science, momentum simply means a multiplication of the mass of an object and its velocity.
Mathematically, momentum is giving by the formula;
Making velocity the subject of formula, we have:
Substituting the given parameters into the formula, we have;
Velocity = 1.5 m/s.
Read more on momentum here: brainly.com/question/15517471
A because the dot nearst to a
Answer:
speed of the mass is 3.546106 m / s
Explanation:
given data
mass = 77.3 g = 77.3 × 
kg
spring constant k = 12.5 N/m
amplitude A = 38.9 cm = 38.9 ×
m
to find out
the speed of the mass
solution
we will apply here conservation energy that is
K.E + P.E = Total energy ..................1
so that Total energy = K.E max = P.E max
we know amplitude so we find out first P.E max that is
PE max = K.E + P.E
(1/2)kA² = (1/2)mv² + (1/2)kx²
kA^² = mv²+ kx²
so here v² will be
v² = k(A² - x²) / m
v = √[(k/m)×(A² - x²)] ............2
here x = (1/2)A so from from 2 equation
v = √[(k/m)×(A² - (A/2)²)]
v = √[(k/m)×(3/4×A²)]
now put all value
v = √[(12.5/ 77.3 × )×(3/4×(38.9 ×)²)]
v = 3.546106 m / s
speed of the mass is 3.546106 m / s
AC or DC
someone use active current or Direct current
Answer:
<em>Details in the explanation</em>
Explanation:
<u>Vertical Launch</u>
When an object is thrown vertically in free air (no friction), it moves upwards at its maximum speed while the acceleration of gravity starts to brake it. At a given time and height, the object stops in mid-air and starts to fall back to the launching point until reaching it with the same speed it was launched.
We are given an expression for the height of an object in function of time t
<em>Please note we have deleted the second 'squared' from the formula since it's incorrect and won't describe the motion of vertical launch.</em>
We now have to evaluate h for the following times, assuming h comes in feet
At t=1 sec
The object is at a height of 48 feet
At t=2 sec
The object is at a height of 64 feet. This is the maximum height the object will reach, as we'll see below
At t=3 sec
The object is at a height of 48 feet. We can clearly see it's returning from the maximum height and is going down
At t=4 sec
The object is at ground level and has returned to the launch point.
