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bagirrra123 [75]
3 years ago
8

What is the difference between a battery losing charge (discharging) and a capacitor losing charge (discharging)?

Physics
1 answer:
aivan3 [116]3 years ago
6 0
The capacitor takes the charge from the battery but the electromotive force EMF of the battery remains same. But, during discharging, the internal resistance of the battery decreases because the charge moves out of the battery to the capacitor.
But, when the capacitor discharges its emf,  decreases with time.
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When a 4.20-kg object is hung vertically on a certain light spring that obeys Hooke's law, the spring stretches 2.00 cm. (a) If
mr_godi [17]

(a) 0.714 cm

First of all, we need to find the spring constant of the spring. This can be done by using Hooke's law:

F=kx

where

F is the force applied on the spring

k is the spring constant

x is the stretching of the spring

At the beginning, the force applied is the weight of the block of m = 4.20 kg hanging on the spring, therefore:

F=mg=(4.20)(9.8)=41.2 N

The stretching of the spring due to this force is

x = 2.00 cm = 0.02 m

Therefore, the spring constant is

k=\frac{F}{x}=\frac{41.2}{0.02}=2060 N/m

Now, a new object of 1.50 kg is hanging on the spring instead of the previous one. So, the weight of this object is

F=mg=(1.50)(9.8)=14.7 N

And so, the stretching of th spring in this case is

x=\frac{F}{k}=\frac{14.7}{2060}=0.00714 m = 0.714 cm

(b) 1.65 J

The work done on a spring is given by:

W=\frac{1}{2}kx^2

where

k is the spring constant

x is the stretching of the spring

In this situation,

k = 2060 N/m

x = 4.00 cm = 0.04 m is the stretching due to the external agent

So, the work done is

W=\frac{1}{2}(2060)(0.04)^2=1.65 J

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4 years ago
It takes 85N of force to accelerate a ball at a rate of 15 m/s². What is the mass of the ball?
Anon25 [30]

Explanation:

F = ma

85 N = m (15 m/s²)

m ≈ 5.7 kg

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3 years ago
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