The answer is c. +2.0 µC
To calculate this, we will use Coulomb's Law:
F = k*Q1*Q2/r²
where F is force, k is constant, Q is a charge, r is a distance between charges.
k = 9.0 × 10⁹ N*m/C²
It is given:
F = 7.2 N
d = 0.1 m = 10⁻¹ m
Q1 = -4.0 µC = 4 * 1.0 × 10⁻⁶ = 4.0 × 10⁻⁶
Q2 = ?
Thus, let's replace this in the formula for the force:
7.2 = 9.0 × 10⁹ * 4.0 × 10⁻⁶ * Q2/(10⁻¹)²
7.2 = 9 * 4 * 10⁹⁻⁶ * Q2/10⁻¹°²
7.2 = 36 × 10³ * Q2 / 10⁻²
Multiply both sides of the equation by 10⁻²:
7.2 × 10⁻² = 36 × 10³ * Q2
⇒ Q2 = 7.2 × 10⁻² / 36 × 10³ = 7.2/36 × 10⁻²⁻³ = 0.2 × 10⁻⁵ = 2 × 10⁻⁶
Since µC = 1.0 × 10^-6:
Q2 = 2 * 1.0 × 10^-6 = 2 µC
Answer:
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Explanation:
The magnitude of the displacement current between the plates is 
Given,
A=4.3*
=
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<h3>Current </h3>
An electrical charge carrier flow known as current often involves electrons or atoms lacking in electrons. The capital letter I is frequently used as a symbol for current. Amperes are the common unit and are denoted by the letter A. A coulomb of electrical charge moves past a certain place in one second as one ampere of current does. Franklin current or conventional current are terms used by physicists to describe how current flows from relatively positive to comparatively negative sites. Negatively charged electrons are the most prevalent charge carriers. They move in a somewhat good direction from relatively negative points.
With e in volts per meter and t in seconds. at t = 0, the field is upward. the plate area is 4. 3 × 10-2 m2. for t > 0, what is the magnitude of the displacement current between the plates?
Learn more about current here:
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<h3>You forgot to add question...Add questions before asking so we can help</h3>
Answer:
36 Ω
Explanation:
Since the 3 resistors are connected in parallel.
The combined resistance of the resistor is
1/Rc = 1/R + 1/R + 1/R ...................... Equation 1
Where Rc = combined resistance of the three resistor, R1 = Resistance of each of the resistor
Rc = R/3 ....................... Equation 2
The formula of power is given as
P = V²/Rc
Rc = V²/P ................ Equation 3
Where V = Voltage, R = Combined Resistance, P = power.
Given: V = 48 V, 192 W.
Substitute into equation 3
Rc = 48²/192
Rc = 12 Ω
From equation 2
Rc = R/3
R = 3Rc
Where Rc = 12 Ω
R = 3×12
R = 36 Ω
Hence the resistance on each resistor = 36 Ω
